Let
x-----------> first <span>odd integer
x+2--------> second consecutive odd integer
x+4-------> third consecutive odd integer
we know that
(x+4)</span>²=15+x²+(x+2)²-------> x²+8x+16=15+x²+x²+4x+4
x²+8x+16=19+2x²+4x-------> x²-4x+3
x²-4x+3=0
using a graph tool----------> to calculate the quadratic equation
see the attached figure
the solution is
x=1
x=3
the answer is
the first odd integer x is 1
the second consecutive odd integer x+2 is 3
the third consecutive odd integer x+4 is 5
4 cups in a at
12 cups = 3qt
3qt =12 cups
So they are equal
Answer:
Step-by-step explanation:
um you can answer them in many ways?
Answer:
Step-by-step explanation:
Solving
5x + -2y = 12
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '2y' to each side of the equation.
5x + -2y + 2y = 12 + 2y
Combine like terms: -2y + 2y = 0
5x + 0 = 12 + 2y
5x = 12 + 2y
Divide each side by '5'.
x = 2.4 + 0.4y
Simplifying
x = 2.4 + 0.4y