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2 years ago

Simplify the following: 3to the power of 2 x 3 to the power of 2??

Mathematics

2 answers:

Veseljchak [2.6K]2 years ago

6 0

<h2>Correct question;</h2>

<h2> $3 {}^{2} \times 3 {}^{2}$ </h2><h2>Required solution;</h2>

<h3>↠ Multiply the terms with the same base by adding their exponents</h3>

<h2> $3 {}^{2 + 2}$ </h2><h3>↠ Add the numbers</h3>

You can also expand it

After expanding the answer will be 81

$expanded \: form \: = 3 \times 3 \times 3 \times 3 = 81$

Hope it helps...

《I own the rights of this answer》

sammy [17]2 years ago

5 0

Answer: The answer is 81x

Step-by-step explanation:

1. You have to apply the exponet rule. so 3 to the 2nd power +2x

2. You then have to add the numbers 2+2=4 so your answer is 81x

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Can somebody please help me?

9966 [12]

28+28+28= 84

28 x 28 x 28 = 21952

hope it helps!:)

4 0

2 years ago

O picatura de ulei cu volumul de 0,3 mm a format pe suprafata apei o pelicula cu aria de 300 cm Calculati grosimea peliculei

lesantik [10]

What did you misspell something or are you foreign

8 0

3 years ago

Mikayla is a waitress who makes a guaranteed $50 per day in addition to tips of 20% of all her weekly customer receipts, t. She

notsponge [240]

Answer:

D. $f(t)=300+0.20t$

Step-by-step explanation:

We have been given that Mikayla is a waitress who makes a guaranteed $50 per day.

Since Miklaya works 6 days per week, so the guaranteed income for one week would be $\$50\times 6=\$300$

We are also told that she gets tips of 20% of all her weekly customer receipts, t. So amount earned from tips would be 20% of t, that is $\frac{20}{100}t=0.20t$ .

Total amount earned in one week would be guaranteed income for 1 week plus 20% of t:

$300+0.20t$

Therefore, our required function is $f(t)=300+0.20t$ and option D is the correct choice.

7 0

2 years ago

f(x)=(2x−1)(3x+5)(x+1) has zeros at x= -5/3, x= -1 and x= 1/2 What is the sign of f on the interval -5/3

Crazy boy [7]

The sign of f on the interval -5/3 is negative

<h3>How to determine the sign?</h3>

The function is given as:

f(x)=(2x−1)(3x+5)(x+1)

The zeros of the function are

x= -5/3, x= -1 and x= 1/2

Next, we plot the graph of the function

At x = -5/3, the function approaches negative infinity

This means that the sign of f on the interval -5/3 is negative

Read more about function intervals at:

brainly.com/question/27831985

#SPJ1

6 0

1 year ago

A 1000-liter (L) tank contains 500 L of water with a salt concentration of 10 g/L. Water with a salt concentration of 50 g/L flo

djverab [1.8K]

Answer:

a) $y(t)=50000-49990e^{\frac{-2t}{25}}$

b) $31690.7 g/L$

Step-by-step explanation:

By definition, we have that the change rate of salt in the tank is $\frac{dy}{dt}=R_{i}-R_{o}$ , where $R_{i}$ is the rate of salt entering and $R_{o}$ is the rate of salt going outside.

Then we have, $R_{i}=80\frac{L}{min}*50\frac{g}{L}=4000\frac{g}{min}$ , and

$R_{o}=40\frac{L}{min}*\frac{y}{500} \frac{g}{L}=\frac{2y}{25}\frac{g}{min}$

So we obtain. $\frac{dy}{dt}=4000-\frac{2y}{25}$ , then

$\frac{dy}{dt}+\frac{2y}{25}=4000$ , and using the integrating factor $e^{\int {\frac{2}{25}} \, dt=e^{\frac{2t}{25}$ , therefore $(\frac{dy }{dt}+\frac{2y}{25}}=4000)e^{\frac{2t}{25}$ , we get $\frac{d}{dt}(y*e^{\frac{2t}{25}})= 4000 e^{\frac{2t}{25}$ , after integrating both sides $y*e^{\frac{2t}{25}}= 50000 e^{\frac{2t}{25}}+C$ , therefore $y(t)= 50000 +Ce^{\frac{-2t}{25}}$ , to find $C$ we know that the tank initially contains a salt concentration of 10 g/L, that means the initial conditions $y(0)=10$ , so $10= 50000+Ce^{\frac{-0*2}{25}}$

$10=50000+C\\C=10-50000=-49990$

Finally we can write an expression for the amount of salt in the tank at any time t, it is $y(t)=50000-49990e^{\frac{-2t}{25}}$

b) The tank will overflow due Rin>Rout, at a rate of $80 L/min-40L/min=40L/min$ , due we have 500 L to overflow $\frac{500L}{40L/min} =\frac{25}{2} min=t$ , so we can evualuate the expression of a) $y(25/2)=50000-49990e^{\frac{-2}{25}\frac{25}{2}}=50000-49990e^{-1}=31690.7$ , is the salt concentration when the tank overflows

4 0

3 years ago