I have to write here as well apparently, but have added answer as picture
Since point Q is the midpoint of GH, that means that GH-GQ=HQ=GQ (since Q is the midpoint). Plugging them in, we get 5x-5-(2x+3)=3x-8=GQ=HQ. Since Q is the midpoint, that means that 3x-8=2x+3=GQ=HQ. Subtracting 2x from both sides as well as adding 8, we get that x=11 and 2(11)+3=25=GQ by plugging x into 2x+3
Step-by-step explanation:
y = mx + c, where m is the slope of the line and c is the y-intercept.
We have y = 3x - 4 as line L.
Slope of line L = 3
=> Slope of line L2 = -1/3
We have y = -1/3 x + c as our line L2 equation.
When x = 9, y = 5.
=> (5) = -1/3 * (9) + c
=> 5 = c - 3, c = 8
Hence the answer is y = -1/3 x + 8.
Answer:
The 1st term is -67
Step-by-step explanation:
I. When Sn =
(
)
If Sn = 124, n = 8 and
= 98
124 = 8/2(a + 98)
124 = 4(a + 98)
124 = 4a + 392
124 - 392 = 4a
-268/4 = a
-67 = 
Hope that help :D
Answer:
Centre (0,0)
Radius √9 = 3
I've attached a graph if the circle with it
Answered by GAUTHMATH