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nasty-shy [4]
3 years ago
5

Please help with this question

Mathematics
1 answer:
pychu [463]3 years ago
5 0

Answer:

2:3 4:6 6:9 8:12 10:15 12: 18  

Step-by-step explanation:

wall is 18 feet

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Point M is the midpoint of AB. The coordinates of point A are (−7, 1) and the coordinates of M are (−2, 2). What are the coordin
notka56 [123]

Answer:

\huge{\boxed{\sf{ ( 3 , 3 ) }}}

Step-by-step explanation:

Co-ordinates of point A = ( -7 , 1 )

Co-ordinates of point M = ( -2 , 2 )

Let the co-ordinates of point B be ( x , y )

A ( -7 , 1 ) \longrightarrow ( x1 , y1 )

B ( x , y ) \longrightarrow ( x2 , y2 )

Now,

Midpoint = (\frac{x1 + x2}{2}  , \frac{y1 + y2}{2} )

⇒( -2 , 2 ) = ( \frac{-7 + x}{2}  , \frac{1 + y}{2} )

Finding the value of x :                    

⇒-2 = \frac{-7 + x}{2}

Do cross multiplication                

⇒-4 = -7 + x

⇒-7 + x = -4

⇒x = -4 + 7

⇒x = 3

Now, finding the value of y

⇒2 = \frac{1+y}{2}

Do cross multiplication

⇒4 = 1+y

⇒1+y = 4

⇒y = 4 - 1

⇒y = 3

Hence, The co-ordinates of point B = ( 3 , 3 )

Hope I helped!

Best regards!

~\text{ TheAnimeGirl}

4 0
3 years ago
How do you complete the square to rewrite y= x^ -6x + 15 in vertex form
Vaselesa [24]
Vertex form of a quadratic equation is y=a(x-h)^{2}+k
where (h, k) is the vertex. 

Our aim is to write the expression y=x^{2} -6x+15 in the form 
y=a(x-h)^{2}+k



y=x^{2} -6x+15

y=x^{2} -2*3*x+15

y=(x^{2} -2*3*x+ 3^{2})-3^{2}+ 15

y=(x-3)^{2}-9+15

y=(x-3)^{2}+6
5 0
3 years ago
I don’t know if this is correct !!!!!!! Please answer correctly !!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!!
Molodets [167]

Answer:

yes i think

Step-by-step explanation:

4 0
3 years ago
Urgent help algebra 2
Vaselesa [24]

Answer:

y = - 1/4 x + 1

Step-by-step explanation:

Find two convenient integer coordinates like   -4,2 and  4, 0

  use these points to  calculate the slope to be -1/4

   intercept is b = 1

y = -1/4 x + 1

3 0
2 years ago
A 15° sector in a circle has an area of 11.9 m2. What is the area of the circle?
DaniilM [7]
<span>A 15° sector in a circle has an area of 11.9 m2. What is the area of the circle?
The area of the circle will be found as follows:
the fraction of the sector=15/360=1/24
the area of the circle will be:
area=(fraction of the circle)/(fraction of the sector)*(area of the sector)
=1/(1/24)</span>×11.9
=285.6 m²
5 0
3 years ago
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