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2 years ago

Five times the sum of x and y decreased by 2x write this as an algebraic expression

Mathematics

2 answers:

sweet [91]2 years ago

5 0

Answer:

5(x+y) - 2x

this is the algebraic expression

Whitepunk [10]2 years ago

3 0

<h2> $x + y \times 5 - 2x$ </h2><h3>This algebraic expression can be formed with the given data.</h3>

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April worked 1 1/2 times as long on her math project as did Carl. Debbie worked 1 1/4 times as long as Sonia. Richard worked 1 3

vlada-n [284]

Answer:

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

Step-by-step explanation:

Some data's were missing so we have attached the complete information in the attachment.

Given:

Number of Hours Carl worked on Math project = $5\frac{1}{4}\ hrs$

$5\frac{1}{4}\ hrs$ can be Rewritten as $\frac{21}{4}\ hrs$

Number of Hours Carl worked on Math project = $\frac{21}{4}\ hrs$

Number of Hours Sonia worked on Math project = $6\frac{1}{2}\ hrs$

$6\frac{1}{2}\ hrs$ can be rewritten as $\frac{13}{2}\ hrs$

Number of Hours Sonia worked on Math project = $\frac{13}{2}\ hrs$

Number of Hours Tony worked on Math project = $5\frac{2}{3}\ hrs$

$5\frac{2}{3}\ hrs$ can be rewritten as $\frac{17}{3}\ hrs.$

Number of Hours Tony worked on Math project = $\frac{17}{3}\ hrs.$

Now Given:

April worked $1\frac{1}{2}$ times as long on her math project as did Carl.

$1\frac{1}{2}$ can be Rewritten as $\frac{3}{2}$

Number of Hours April worked on math project = $\frac{3}{2}$ $\times$ Number of Hours Carl worked on Math project

Number of Hours April worked on math project = $\frac{3}{2}\times \frac{21}{4} = \frac{63}{8}\ hrs \ \ Or \ \ 7\frac{7}{8} \ hrs$

Also Given:

Debbie worked $1\frac{1}{4}$ times as long as Sonia.

$1\frac{1}{4}$ can be Rewritten as $\frac{5}{4}$ .

Number of Hours Debbie worked on math project = $\frac{5}{4}$ $\times$ Number of Hours Sonia worked on Math project

Number of Hours Debbie worked on math project = $\frac{5}{4}\times \frac{13}{2}= \frac{65}{8}\ hrs \ \ Or \ \ 8\frac{1}{8}\ hrs$

Also Given:

Richard worked $1\frac{3}{8}$ times as long as tony.

$1\frac{3}{8}$ can be Rewritten as $\frac{11}{8}$

Number of Hours Richard worked on math project = $\frac{11}{8}$ $\times$ Number of Hours Tony worked on Math project

Number of Hours Debbie worked on math project = $\frac{11}{8}\times \frac{17}{3}= \frac{187}{24}\ hrs \ \ Or \ \ 7\frac{19}{24}\ hrs$

Hence We will match each student with number of hours she worked.

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

5 0

3 years ago

Read 2 more answers

Observe

slega [8]

Answer:

They both have the same y-intercept

one is a straight line and the other is not

I used my brain to solve it.please mark me as the brainiest,It would mean a lot to me.

6 0

3 years ago

The ratio of girls to boys in the photography club is 7 to 3. Which ratio could represent the members of the photography club?

MA_775_DIABLO [31]

Answer:

C) 21 girls : 9 boys

Step-by-step explanation:

You just have to compare the ratio you're given to the answers and see if the ratios from the answers match up to the ratio you were given. The reason C is the answer is because if you divide by 3 in the ration, it is the same as the ratio you were given, 7:3

8 0

3 years ago

Eloise is planning on retiring soon. When she first began working she invested $1500 in a retirement fund. The percent increase

cupoosta [38]

$2925 she would have left in her account :)

6 0

3 years ago

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Need answer ASAP !!!!

kondor19780726 [428]

Answer:

y = -1/4x^2 - x + 3

Step-by-step explanation:

(-6,0)

(-4,3)

(2,0)

36a - 6b + c = 0

16a -4b + c = 3

4a + 2b + c = 0

c = -4a - 2b

36a - 6b - 4a -2b = 0

16a - 4b -4a - 2b = 3

32a -8b = 0

12a - 6b = 3

4a - b = 0

4a - 2b = 1

b = -1

4a + 1 = 0

4a = -1

a = -1/4

c = 1 + 2 = 3

y = -1/4x^2 - x + 3

4 0

3 years ago

Read 2 more answers