A plumber charges 25$ for a service call plus 50$ per hour of service.write an equation for the cost,C,after h hours of service.

1 answer:

5 0

We know that C is dependent on how many hours of service was done. We also know that C is linearly dependent on how many hours of service was done because it's a constant $50 per hour.

So, the equation would be a linear equation in the form C = 50h + L where h is the number of hours and L is the y-intercept.

Since there is an initial charge of $25, when h = 0, C = $25 -> L = $25.

So, the equation is C = 50h + 25.

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~~~15 POINTS~~~

REY [17]

Let's call bicycles 'b' and unicycles 'u'
Note that bicycles have 2 tires, and unicycles have 1 tire.

We can make two equations:

b = u + 8
2b + 1u = 46

Solving the first equation for u, we get:

u = b - 8

Plug that equation into the second, and we get:

2b + (b - 8) = 46

Subtract 2b on both sides.

1(b - 8) = 46 - 2b

Basically, I used b and your question used n.

The correct answer is: D. 1(n - 8) = 46 - 2n.

7 0

3 years ago

Lines b and c are parallel.

fomenos

Where is the diagram?
Can't be solved without it.

3 0

3 years ago

Read 2 more answers

Solve for a. 1/5(25−5a)=4−a

aalyn [17]

1/5(25-5a)=4-a
⇔5-a=4-a
<span>NO SOLUTION</span>

3 0