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lesya [120]
3 years ago
10

Aaron bought a new TV for $1,224. He is paying it off over a period of 12 months. How much will Aaron pay per month for his new

TV?
Mathematics
2 answers:
evablogger [386]3 years ago
7 0

Aaron will have to pay $102 a month. Just divide $1,224 by 12!

boyakko [2]3 years ago
3 0

1224 / 12 = 102

He will be paying $102 a month for his TV

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A. <span>–4.28 > –3.56 * should be less than
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In dealing with negative numbers, the greater the negative number is, the lesser its value. 4.37 is a greater number than 1.63 in its positive form, however, its negative form give 4.37 a lesser value than 1.63 in its negative form. 
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Algebra 2: Functions, graphing, and transformations.
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The answer is  “C” (Shifts left 3 units)

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The American Management Association is studying the income of store managers in the retail industry. A random sample of 49 manag
VashaNatasha [74]

Answer:

a) The 95% confidence interval for the income of store managers in the retail industry is ($44,846, $45,994), having a margin of error of $574.

b) The interval mean that we are 95% sure that the true mean income of all store managers in the retail industry is between $44,846 and $45,994.

Step-by-step explanation:

Question a:

We have to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a p-value of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.96\frac{2050}{\sqrt{49}} = 574

The lower end of the interval is the sample mean subtracted by M. So it is 45420 - 574 = $44,846.

The upper end of the interval is the sample mean added to M. So it is 45420 + 574 = $45,994.

The 95% confidence interval for the income of store managers in the retail industry is ($44,846, $45,994), having a margin of error of $574.

Question b:

The interval mean that we are 95% sure that the true mean income of all store managers in the retail industry is between $44,846 and $45,994.

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