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BartSMP [9]
3 years ago
12

Divide to find equivalent fractions 8/12=

Mathematics
1 answer:
satela [25.4K]3 years ago
3 0

8/12 ÷ 4/4 = 2/3

answer: 2/3

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Find the slope of the line that passes through (10,3) and (3,12).
Gnoma [55]

Answer:

-9/7

Step-by-step explanation:

slope \: of \: line  \\  \\ =  \frac{12 - 3}{3 - 10}  \\  \\  =  \frac{9}{ - 7}  \\  \\  =   - \frac{9}{7}

5 0
3 years ago
A cylindrical jar has a diameter of 9 in. and a height of 12 in. The water surface is 2.5 in. from the top. About how much water
Snowcat [4.5K]
It he correct answer is a
7 0
3 years ago
PLEASE HELP!! HURRY BUT I DON'T WANT GUESSES
Lorico [155]
The square on the hypotenuse is skew and impossible to visually validate. There's nothing to sum. It is a simple calculation to note that <span><span><span>32</span>+<span>42</span>=<span>52</span></span><span><span>32</span>+<span>42</span>=<span>52</span></span></span><span>, but its picture doesn't 'say' that the angle between the 3 and 4 sided square must be 90 degrees.


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7 0
3 years ago
What is the equation of a line that has a slope of −12 and a y-intercept of 3? Express your answer in slope-intercept form.
Elena L [17]

If given the slope and y-intercept, you can directly get the slope intercept form as

y = -12x + 3

6 0
3 years ago
The General Social Survey asked a large number of people how much time they spent watching TV each day. The mean number of hours
DerKrebs [107]

Answer:

Yes, we can conclude that the population standard deviation of TV watching times for teenagers is less than 2.66

Step-by-step explanation:

H0 : σ² = 2.66²

H1 : σ² < 2.66²

X²c = (n - 1)*s² ÷ σ²

sample size, n = 40

Sample standard deviation, s = 1.9

X²c = ((40 - 1) * 1.9²) ÷ 2.66²

X²c = 140.79 ÷ 7.0756

X²c = 19.897

Using a confidence level of 95%

Degree of freedom, df = n - 1 ; df = 40 - 1 = 39

The critical value using the chi distribution table is 25.6954

Comparing the test statistic with the critical value :

19.897 < 25.6954

Test statistic < Critical value ; Reject the Null

Hence, we can conclude that the population standard deviation of TV watching times for teenagers is less than 2.66

8 0
3 years ago
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