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Lynna [10]
3 years ago
7

Need Help Please

Computers and Technology
1 answer:
erastova [34]3 years ago
4 0

Answer:

1. siblings + 1

2. numberOfPizzas * pizzaCost

3. alienGreeting + alienGreeting2

4. color1 === color2

5. value1 - value2

6. console.log(gradeAverage === gradeAverage2)

7. numberToString + numberToString2

8. numberOfStudents / numberOfClassrooms

9. console.log(carSpeed === truckSpeed)

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Big-O notation is a way to describe a function that represents the n amount of times a program/function needs to be executed. 

(I'm assuming that := is a typo and you mean just =, by the way) 

In your case, you have two loops, nested within each other, and both loop to n (inclusive, meaning, that you loop for when i or j is equal to n), and both loops iterate by 1 each loop.

This means that both loops will therefore execute an n amount of times. Now, if the loops were NOT nested, our big-O would be O(2n), because 2 loops would run an n amount of times.

HOWEVER, since the j-loop is nested within i-loop, the j-loop executes every time the i-loop <span>ITERATES. 
</span>
As previously mentioned, for every i-loop, there would be an n amount of executions. So if the i-loop is called an n amount of times by the j loop (which executes n times), the big-O notation would be O(n*n), or O(n^2). 

(tl;dr) In basic, it is O(n^2) because the loops are nested, meaning that the i-loop would be called n times, and for each iteration, it would call the j-loop n times, resulting in n*n runs.

A way to verify this is to write and test program the above. I sometimes find it easier to wrap my head around concepts after testing them myself.
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