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3 years ago

What is the solution for this set of equation (2r-3)-4=37

Mathematics

1 answer:

Alex777 [14]3 years ago

5 0

Answer:

(2r-3)-4=37

or,(2r-3)=37+4

or,2r-3=41

or,2r=41+3

or,2r=44

or, r= 44/2

hence , r= 22

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Step-by-step explanation:

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The solution for s in the given equation is $s = C-nD$

The question seems to be incomplete

Here is the complete question:

Solve for s in this equation $D= \frac{C-s}{n}$ Depreciation.

To solve for s, that means we should make s the subject of the equation

From the given equation,

$D= \frac{C-s}{n}$

To solve for s, first multiply both sides by n to clear the fraction

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$n\times D= n \times \frac{C-s}{n}$

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∴ $s = C-nD$

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Learn more here: brainly.com/question/21406377

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