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natima [27]
2 years ago
12

The graph box linear function f passes through the point (1, -9) and has a slope of 3

Mathematics
1 answer:
Marat540 [252]2 years ago
3 0

9514 1404 393

Answer:

  C) 4

Step-by-step explanation:

The point-slope equation of the line is ...

  y -k = m(x -h) . . . . . line with slope m through point (h, k)

  y +9 = 3(x -1) . . . . . line with slope 3 through point (1, -9)

For y=0 (the 0 of the function), we have ...

  9 = 3(x -1)

  3 = x -1

  4 = x

The x-intercept is (4, 0).

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Answer:

The equation of the parabola that models the path of the long jumper through the air is y = -x^{2}+12\cdot x -27.

Step-by-step explanation:

Mathematically, we know that parabolas are second-order polynomials and every second-order polynomials, also known as quadratic functions, can be constructed by knowing three different points of the curve. The standard form of the parabola is:

y = a\cdot x^{2}+b\cdot x + c

Where:

x - Horizontal distance from the start line, measured in meters.

y - Height of the long jumper, measured in meters.

a, b, c - Polynomial constants, measured in \frac{1}{m}, dimensionless and meters, respectively.

If we know that (x_{1},y_{1}) = (3\,m, 0\,m), (x_{2},y_{2}) = (8\,m, 0.05\,m) and (x_{3}, y_{3}) = (9\,m, 0\,m), this system of linear equations is presented below:

9\cdot a + 3\cdot b + c = 0 (Eq. 1)

81\cdot a + 9\cdot b + c = 0 (Eq. 2)

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The coefficients of the polynomial are, respectively:

a = -\frac{1}{100}, b = \frac{3}{25}, c = -\frac{27}{100}

The equation of the parabola that models the path of the long jumper through the air is y' = -\frac{1}{100}\cdot x^{2}+\frac{3}{25}\cdot x -\frac{27}{100}.

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y = 100\cdot y'

Then, we get that:

y = -x^{2}+12\cdot x -27

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The equation of the parabola that models the path of the long jumper through the air is y = -x^{2}+12\cdot x -27.

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Step-by-step explanation:

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Answer:

  a.  $3,455.20

Step-by-step explanation:

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