Answer:
yea 24
Step-by-step explanation:

Multiply the square root of 3 by the square root of 2 and itself.
The 3 cancels itself out and then you get A
Answer:
y= -2/3x-4
Step-by-step explanation:
The question is an illustration of combination and there are 729 potential pass codes available
<h3>How to determine the number of potential pass codes?</h3>
The given parameters are
Symbols available = 9
Length of pass code = 3
From the question, we understand that a symbol may be entered any number of times.
This means that each of the 9 available symbols can be used three times
So, the number of potential pass codes is
Passcodes = 9 * 9 * 9
Evaluate the product
Passcodes = 729
Hence, there are 729 potential pass codes available
Read more about combination at:
brainly.com/question/11732255
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