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seraphim [82]
3 years ago
6

100 POINTS Use the function f(x) = 5x2 + 2x − 3 to answer the questions. Part A: Completely factor f(x). (2 points) Part B: What

are the x-intercepts of the graph of f(x)? Show your work. (2 points) Part C: Describe the end behavior of the graph of f(x). Explain. (2 points) Part D: What are the steps you would use to graph f(x)? Justify that you can use the answers obtained in Part B and Part C to draw the graph. (4 points)

Mathematics
1 answer:
navik [9.2K]3 years ago
3 0

Answer:

see below

Step-by-step explanation:

f(x) = 5x^2 + 2x − 3

        (5x-3) ( x+1)

To find the x intercepts, set this equal to zero

0=  (5x-3) ( x+1)

Using the zero product property

5x-3 =0     x+1 =0

5x=3             x =-1

x = 3/5             x = -1     are the zeros

End behavior

x = -infinity

5 ( -infinity )^2

5 (infinity) = infinity

as x goes to negative infinity, f(x) goes to infinity

x = infinity

5 ( infinity )^2

5 (infinity) = infinity

as x goes to  infinity, f(x) goes to infinity

To plot the function, we need to plot the zeros ( or x intercepts) and the end behavior as well as the vertex to plot the graph

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Three trucks delivered potatoes to a warehouse. The first truck delivered 5 7/8 tons of potatoes, the second one 6 1/2 tons more
mina [271]

Answer:

12 5/8 tons were delivered by the third truck

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6 0
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Read 2 more answers
Suppose that we don't have a formula for g(x) but we know that g(3) = −5 and g'(x) = x2 + 7 for all x. (
True [87]
So it tells us that g(3) = -5 and g'(x) = x^2 + 7.

So g(3) = -5 is the point (3, -5)
Using linear approximation
g(2.99) is the point (2.99, g(3) + g'(3)*(2.99-3))

now we just need to simplify that
(2.99, -5 + (16)*(-.01)) which is (2.99, -5 + -.16) which is (2.99, -5.16)
So g(2.99) = -5.16 

Doing the same thing for the other g(3.01)
(3.01, g(3) + g'(3)*(3.01-3))
(3.01, -5 + 16*.01) which is (3.01, -4.84)
So g(3.01) = -4.84

So we have our linear approximation for the two. 

If you wanted to, you could check your answer by finding g(x).  Since you know g'(x), take the antiderivative and we will get 
g(x) = 1/3x^3 + 7x + C
Since we know g(3) = -5, we can use that to solve for C
1/3(3)^3 + 7(3) + C = -5 and we find that C = -35
so that means g(x) = (x^3)/3 + 7x - 35

So just to check our linear approximations use that to find g(2.99) and g(3.01)

g(2.99) = -5.1597
g(3.01) = -4.8397

So as you can see, using the linear approximation we got our answers as
g(2.99) = -5.16
g(3.01) = -4.84
which are both really close to the actual answer.  Not a bad method if you ever need to use it. 
5 0
3 years ago
Which real numbers are zeros of the function?
Galina-37 [17]

Answer: 0, 1/3, -3, 3

Explanation:

I got this question right on k12.

<h2>sincerely, The greatest </h2>

7 0
3 years ago
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