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OLga [1]
3 years ago
14

The average number of points a basketball team scored for three games was 63 points. In the first two games they scored the same

number of points which was 6 points more than they scored in the third game. Write and solve an equation to find the number of points the team scored in each game.
Mathematics
2 answers:
hoa [83]3 years ago
8 0

Answer:65, 65 and 59

Step-by-step explanation:

If represented by x and y, (2x+y)/3=63

So 2x+y=189

So if x=y+6

Put the value of x into the equation

2x + y = 189

2(y + 6) + y = 189

2y + 12 + y = 189

3y = 189 - 12

3y = 177

y = 177/3

y = 59

Therefore, x = y + 6 = 59 + 6 = 65

Diano4ka-milaya [45]3 years ago
6 0

Answer:

First Game: 65 points

Second Game : 65 points

Third Game : 59 points

Step-by-step explanation:

Average = sum of values/number of values

The number of values = 3, an d average = 63

63 = x/3

63 * 3 = x

189 = x

Now 189 is the sum of points over two games.

Their first two games are worth the same, so lets call that s +s = 2s

Their 3rd game is worth 6 less points than s, so s-6

let's add up all the terms:

2s + (s - 6) = 3s - 6

Solve:

3s - 6 = 189

3s = 195

s = 65

The first two games are worth 65, and the third game is worth 65 - 6 = 59.

-Chetan K

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Vamos calcular quantos metros de corda Maria comprou na segunda vez:

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Ela pagou R$ 9,60 a mais na segunda compra do que na primeira.


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Agora vamos calcular quanto ela pagou por metro:

9,60 ÷ 12 = 0,80


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Para saber quanto Maria gastou na primeira compra multiplicamos os 21 metros pelo seu valor unitário:

21 × 0,8 = 16,80


Resposta: R$ 16,80 Letra B



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We have been given that a rectangular auditorium seats 1702 people. Also, the number of seats in each row exceeds the number of rows by 9.

Let us assume that there are x rows in the auditorium. Therefore, there must be (x+9) seats in the each row. This will also be equal to the number of columns in the auditorium.

Therefore, we can set up an equation as:

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What is the modulus and argument after (StartRoot 3 EndRoot) (cosine (StartFraction pi Over 18 EndFraction) + I sine (StartFract
fgiga [73]

Answer:

|z| = 27 -- Modulus

\theta = \frac{\pi}{3} --- Argument

Step-by-step explanation:

Given

((\sqrt 3)(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18}))^6

Required

Determine the modulus and the argument

We have that:

z = ((\sqrt 3)(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18}))^6

Expand:

z = (\sqrt 3)^6(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18})^6

z = 27(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18})^6

A complex equation can be expressed as:

z = |z| e^{i\theta}

Where

|z| = modulus

\theta = argument

Where

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So:

z = 27(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18})^6 becomes

z = 27(e^{i\frac{\pi}{18}})^6

By comparison:

e^{i\theta} = (e^{i\frac{\pi}{18}})^6

This gives:

{i\theta} = i\frac{\pi}{18}}*6

{i\theta} = i\frac{6\pi}{18}}

{i\theta} = i\frac{\pi}{3}}

Divide through by i

\theta = \frac{\pi}{3}

Hence, the modulus, z is:

|z| = 27

And the argument \theta is

\theta = \frac{\pi}{3}

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