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Soloha48 [4]
3 years ago
14

I keep getting it wrong help

Mathematics
1 answer:
navik [9.2K]3 years ago
5 0
The answer is c, the x intercept is where the line touches the x axis
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Solve the equation 5 - 8n = 10 for n.​
nikklg [1K]

Answer:

-⅝

Step-by-step explanation:

5-8n=10

-5. -5

-8n=5

÷-8. ÷-8

n=-⅝

7 0
3 years ago
How to write a cubic function that passes through the points?
Bad White [126]
<span>Please be more clear with what you want for your answer. </span>
8 0
3 years ago
A business owner noted the features of the 100 cars parked at the business. Here are the results:
8_murik_8 [283]

Answer:

The probability of a selected car being a 4 door car, given that the car has a sunroof = 0.40

Step-by-step explanation:

The complete question is presented in the attached image.

The conditional probability, of event A happening, given that event B has happened, P(A|B), is given mathematically as

P(A|B) = P(A n B) ÷ P(B)

So, the required probability of a selected car being a 4 door car, given that the car has a sunroof is given as

P (4 doors | sunroof)

= P (4 doors n sunroof) ÷ P(sunroof)

Note that the probability of an event is given as the number of elements in that event divided by the Total number of events.

P (4 doors n sunroof)

= n (4 doors n sunroof) ÷ n (total)

From the Venn Diagram in the attached image,

n (4 doors n sunroof) = 20 + 0 = 20

n (total) = 100

P (4 doors n sunroof) = (20/100) = 0.20

P(sunroof) = n(sunroof) ÷ n(total)

n(sunroof) = 12 + 18 + 20 + 0 = 50

n(total) = 100

P(sunroof) = (50/100) = 0.50

P (4 doors | sunroof)

= P (4 doors n sunroof) ÷ P(sunroof)

= (0.20/0.50) = 0.40

Hope this Helps!!!

5 0
3 years ago
Does anyone know the the answer to the second algebra question? Will give brainiest
astraxan [27]

Answer:

\sqrt[3]{x^{10} }[\tex]Step-by-step explanation:Exponential Rules:[tex]x^{a} + x^{b} = x^{a + b}

\sqrt[b]{x^{a} } =x^{\frac{a}{b} } Original Equation:[tex]\sqrt[3]{x^{10} }  = x^{\frac{10}{3} } Answer:[tex]\sqrt[3]{x^{10} }[\tex]Convert the cubed root to a power. Cubed root = [tex]\frac{1}{3}

x^{3} x^{\frac{1}{3} }

Convert them, so they have a common denominator - \frac{1}{3}

\frac{3}{1}  * \frac{1}{3}=  \frac{9}{3}

\frac{9}{3} + \frac{1}{3} = \frac{10}{3}

[tex]\sqrt[3]{x^{10} }[\tex] = [tex]x^{\frac{10}{3} } [\tex]

8 0
3 years ago
Write an algebraic expression that models the situation
ladessa [460]

Answer:

19

Step-by-step explanation:

just 19

5 0
4 years ago
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