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nikitadnepr [17]
3 years ago
7

Slope intercept form of a line that has a slope of -3/4 and passes through (4, 3)

Mathematics
1 answer:
tia_tia [17]3 years ago
6 0
<h3><u>Explanation</u></h3>
  • First Method

We have the given slope value and the coordinate point that the graph passes through.

y = mx + b

where m = slope and b = y-intercept. Substitute the value of slope in the equation.

y =  -  \frac{3}{4} x + b

We have the given coordinate point as well. After we substitute the slope, we substitute the coordinate point value in the equation.

3 =  -  \frac{3}{4} (4) + b \\

<u>Solve</u><u> </u><u>the</u><u> </u><u>equation</u><u> </u><u>for</u><u> </u><u>b-term</u>

3 =  - 3 + b \\ 3 + 3 = b \\ 6 = b

The value of b is 6. We substitute the value of b in the equation.

y =  -  \frac{3}{4} x + 6

  • Second Method

We can also use the Point-Slope form to solve the question.

y - y_1 = m(x - x_1)

Given the y1 and x1 = the coordinate point value.

Substitute the slope and coordinate point value in the point slope form.

y - 3 = -  \frac{3}{4} (x - 4)

<u>Simplify</u><u>/</u><u>Convert</u><u> </u><u>into</u><u> </u><u>Slope-intercept</u>

y =  -  \frac{3}{4} (x - 4) + 3 \\ y =  -  \frac{3}{4} x +  \frac{12}{4}  + 3 \\ y =  -  \frac{3}{4} x + 3 + 3 \\y =  -  \frac{3}{4} x + 6

<h3><u>Answer</u></h3>

<u>\large \boxed {y =  -  \frac{3}{4} x + 6}</u>

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Lets call X₁ the time at which you arrive, and X₂ the time at which Bob arrives. Both are random variables with uniform density in the interval [0, 60] (in minutes). Their joint distribuition is uniform over the square in the image, with value P = 1/(60*60) = 1/3600.

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It makes sense, beacuse its equally probable for you or Bob to arrive earlier, as both have uniform density over the time interval.

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