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lisov135 [29]
4 years ago
10

How to answer this ?

Mathematics
2 answers:
hichkok12 [17]4 years ago
5 0

Answer:

a)3,6,9,12,15,18,24 b)7,14,21,28,35,52,49,56

a)16 b)40 c)24 d)36

Step-by-step explanation:


Lyrx [107]4 years ago
5 0
Those are the answers to the problems

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Tomtit [17]

Answer:64

Step-by-step explanation:

67

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3 years ago
If you spin the spinner 12 times, what is the best prediction possible for the number of times it will land on pink?
Norma-Jean [14]
2/3 if that’s the question
3 0
3 years ago
An investigator claims, with 95 percent confidence, that the interval between 10 and 16 miles includes the mean commute distance
RideAnS [48]

Answer:

Hello the options to your question is missing below are the options

 A) if sample means were obtained for a long series of samples, approximately 95 percent of all sample means would be between 10 and 16 miles

B.the unknown population mean is definitely between 10 and 16 miles

C.if these intervals were constructed for a long series of samples, approximately 95 percent would include the unknown mean commute distance for all Californians

D.the unknown population mean is between 10 and 16 miles with probability .95

Answer : if these intervals were constructed for a long series of samples, approximately 95 percent would include the unknown mean commute distance for all Californians  ( c )

Step-by-step explanation:

95%  confidence

interval = 10 to 16 miles

To have 95% confidence signifies that if these intervals were constructed for a long series of samples, approximately 95 percent would include the unknown mean commute distance for all Californians

confidence interval covers a range of samples/values in the interval and the higher the % of the confidence interval the more precise the interval is,

7 0
3 years ago
Prove this identity sin^2θcsc^2θ=sin^2θ+cos^2θ by simplifying both sides of the equation.
Gwar [14]

\bf \begin{array}{rllll} sin^2(\theta )csc^2(\theta )&=&sin^2(\theta )+cos^2(\theta )\\\\ ~~\begin{matrix} sin^2(\theta ) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ \cdot \cfrac{1^2}{~~\begin{matrix} sin^2(\theta ) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }&=&1\\\\ 1^2&=&1\\ 1&=&1 \end{array}

8 0
3 years ago
Read 2 more answers
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agasfer [191]
It would be the 2nd answer....your initial value (read from the left of the line graph) is 4.....following the line to the first even point you can see it has dropped 3 for the 4 points it has moved to the right....giving -3/4 as the rate of change.
3 0
3 years ago
Read 2 more answers
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