Answer:
x=45
Step-by-step explanation:
2/5x-10=8
2/5x=18
x=18÷2/5
x=18(5/2)
x=45
The first is proportional the second is proportional and the third is not proportional
Answer:
uhh either 4/4 1 or 2/2
Step-by-step explanation:
if the words covered by the light reflection says "the shaded part", then there are 4 total pieces, which means all four are shaded.
The standard form of a quadratic equation is

, while the vertex form is:

, where (h, k) is the vertex of the parabola.
What we want is to write

as

First, we note that all the three terms have a factor of 3, so we factorize it and write:

.
Second, we notice that

are the terms produced by

, without the 9. So we can write:

, and substituting in

we have:
![\displaystyle{ y=3(x^2-6x-2)=3[(x-3)^2-9-2]=3[(x-3)^2-11]](https://tex.z-dn.net/?f=%5Cdisplaystyle%7B%20y%3D3%28x%5E2-6x-2%29%3D3%5B%28x-3%29%5E2-9-2%5D%3D3%5B%28x-3%29%5E2-11%5D)
.
Finally, distributing 3 over the two terms in the brackets we have:
![y=3[x-3]^2-33](https://tex.z-dn.net/?f=y%3D3%5Bx-3%5D%5E2-33)
.
Answer:
Answer:

Step-by-step explanation:
Consider the selling of the units positive earning and the purchasing of the units negative earning.
<h3>Case-1:</h3>
- Mr. A purchases 4 units of Z and sells 3 units of X and 5 units of Y
- Mr.A earns Rs6000
So, the equation would be

<h3>Case-2:</h3>
- Mr. B purchases 3 units of Y and sells 2 units of X and 1 units of Z
- Mr B neither lose nor gain meaning he has made 0₹
hence,

<h3>Case-3:</h3>
- Mr. C purchases 1 units of X and sells 4 units of Y and 6 units of Z
- Mr.C earns 13000₹
therefore,

Thus our system of equations is

<u>Solving </u><u>the </u><u>system </u><u>of </u><u>equations</u><u>:</u>
we will consider elimination method to solve the system of equations. To do so ,separate the equation in two parts which yields:

Now solve the equation accordingly:

Solving the equation for x and y yields:

plug in the value of x and y into 2x - 3y + z = 0 and simplify to get z. hence,

Therefore,the prices of commodities X,Y,Z are respectively approximately 1477, 1464, 1437