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2 years ago

Which inequality is true when the value of y is 9?

Mathematics

1 answer:

goldfiish [28.3K]2 years ago

8 0

Answer:

y + 8 > 0.5

Step-by-step explanation:

Let's take a look at each one individually to see whether y = 9 is a possible value for the inequality. First, we'll check out y + 8 < 0.5. If we replace y with 9, we get 9 + 8 < 0.5. 9 plus 8 is 17, so now we have 17 < 0.5. That's not true, because 17 is not smaller than 0.5. So we know that this option is incorrect.

Next, let's look at -y + 8 > 0.5. We replace y with 9 and get -9 + 8 > 0.5, or -1 > 0.5. This isn't true either! -1 is smaller than 0.5, not greater. So this isn't the option either.

We'll now look at y + 8 > 0.5. If we replace y with 9, we get 9 + 8 > 0.5 or 17 > 0.5. This is true, so we can be confident that this is the correct answer! Let's just test the last answer for good measure though.

Is -9 + 8 greater than -0.5? Well, -9 plus 8 is equal to -1, and -1 is not greater than -0.5. So we were correct. y + 8 > 0.5 is true when the value of y is 9.

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12% of 80 working out

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How to do the problem:
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What I mean:

You want 12% of 80
so first change 12% into a decimal
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Then multiply that decimal by the whole
Since you want 12% of 80, 80 is the whole

that means you do .12 * 80
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Thus(answer)
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2 years ago

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Answer:
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2 years ago

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Answer:

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2 years ago

Rationalize the denominator of sqrt -49 over (7 - 2i) - (4 + 9i)

zubka84 [21]

$\sqrt{ \frac{-49}{(7-2i)-(4+9i) } } 
$

This one is quite the deal, but we can begin by distributing the negative on the denominator and getting rid of the parenthesis:

$\frac{ \sqrt{-49}}{7-2i-4-9i}$

See how the denominator now is more a simplification of like terms, with this I mean that you operate the numbers with an "i" together and the ones that do not have an "i" together as well. Namely, the 7 and the -4, the -2i with the -9i.
Therefore having the result:

$\frac{ \sqrt{-49} }{3-11i}$

Now, the $\sqrt{-49}$ must be respresented as an imaginary number, and using the multiplication of radicals, we can simplify it to $\sqrt{49} \sqrt{-1}$
This means that we get the result 7i for the numerator.

$\frac{7i}{3-11i}$

In order to rationalize this fraction even further, we have to remember an identity from the previous algebra classes, namely: $x^2 - y^2 =(x+y)(x-y)$
The difference of squares allows us to remove the imaginary part of this fraction, leaving us with a real number, hopefully, on the denominator.

$\frac{7i (3+11i)}{(3-11i)(3+11i)}$

See, all I did there was multiply both numerator and denominator with (3+11i) so I could complete the difference of squares.
See how $(3-11i)(3+11i)= 3^2 -(11i)^2$ therefore, we can finally write:

$\frac{7i(3+11i)}{3^2 - (11i)^2 }$

I'll let you take it from here, all you have to do is simplify it further.
The simplification is quite straightforward, the numerator distributed the 7i. Namely the product $7i(3+11i) = 21i+77i^2$ .
You should know from your classes that i^2 = -1, thefore the numerator simplifies to $-77+21i$
You can do it as a curious thing, but simplifying yields the result:
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3 years ago

two functions a and b are described as follows function a: y=8x+3 function b:the rate of change is 1 and the y intercept is 4 ho

AnnZ [28]

Answer:

Step-by-step explanation:

rate of change of function not necessary mean linear, it can be the slope of a tangent line.

a: y=8x+3 slope = 8

b: rate of change: 1

8-1=7

I wish this is true...

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2 years ago