Ask question

Ask question

All categories

3 years ago

8

Max's mix mixing oil and gas for his moped to use is 3.75 L of gas in 1.5 L of oil how many liters of gas are used per liter of

oil

1 answer:

Troyanec [42]3 years ago

4 0

Answer:

b

Step-by-step explanation:

You might be interested in

Suppose a bus arrives at a bus stop every 35 minutes

Ratling [72]

Answer:

3/7

Step-by-step explanation:

The probability of at least is 1 - the probability of at most

P(at least x) = 1 - P(at most x)

The given is:

1. A bus arrives at a bus stop every 35 minutes

2. You arrive at the bus stop at a random time

3. You will have to wait at least 20 minutes for the bus

∵ The bus arrives at a bus stop every 35 minutes

∵ You arrive at the bus stop at a random time

∵ You will wait at most for 20 minutes for the bus

∴ P(at most 20 minutes) =

∵ P(at least 20 minutes) = 1 - P(at most 20 minutes)

∴ P(at least 20 minutes) = 1 -

∴ P(at least 20 minutes) =

- Simplify the fraction by divide up and down by 5 and you will get your answer!

please mark me brainliest!

5 0

3 years ago

Find the area of the region which is inside the polar curve r=5sin(θ) but outside r=4. Round your answer to four decimal places

natka813 [3]

The area of the region which is inside the polar curve r = 5 sinθ but outside r = 4 will be 3.75 square units.

<h3>What is an area bounded by the curve?</h3>

When the two curves intersect then they bound the region is known as the area bounded by the curve.

The area of the region which is inside the polar curve r = 5 sinθ but outside r = 4 will be

Then the intersection point will be given as

$\rm 5 \sin \theta = 4\\\\\theta = 0.927 , 2.214$

Then by the integration, we have

$\rightarrow \dfrac{1}{2} \times \int _{0.927}^{2.214}[ (5 \sin \theta)^2 - 4^2] d\theta \\\\\\\rightarrow \dfrac{1}{2} \times \int _{0.927}^{2.214} [25\sin ^2 \theta - 16] d\theta \\\\\\\rightarrow \dfrac{1}{2} \times \int _{0.927}^{2.214} [ \dfrac{25}{2}(1 - \cos 2\theta ) - 16] d\theta \\$

$\rightarrow \dfrac{1}{2} [\dfrac{25 \theta }{5} - \dfrac{25 \cos 2\theta }{2} - 16\theta]_{0.927}^{2.214} \\\\\\\rightarrow \dfrac{1}{2} [\dfrac{25(2.214 - 0.927) }{5} - \dfrac{25 (\cos 2\times 2.214 - \cos 2\times 0.927) }{2} - 16(2.214 - 0.927]\\$

On solving, we have

$\rightarrow \dfrac{1}{2} \times 7.499\\\\\rightarrow 3.75$

Thus, the area of the region is 3.75 square units.

More about the area bounded by the curve link is given below.

brainly.com/question/24563834

#SPJ4

5 0

2 years ago

June and Angad have played 30 tennis matches.

Bad White [126]

Answer:

Step-by-step explanation:

a) P (June) = 7/15

b) P (Angad) = 8/15

7 0

2 years ago

The center of a hyperbola is (−4,3) , and one vertex is (−4,7) . The slope of one of the asymptotes is 2.

Monica [59]

Answer:

The answer to your question is below

Step-by-step explanation:

C (-4, 3)

V (-4, 7)

asymptotes = 2 = $\frac{b}{a}$

- This is a vertical hyperbola, the equation is

$\frac{(y - k)^{2} }{a^{2} } + \frac{(x - h)^{2} }{b^{2} } = 1$

slope = 2

a is the distance from the center to the vertex = 4

b = 2(4) = 8

$\frac{(y - 3)^{2} }{4^{2} } + \frac{(x + 4)^{2} }{8^{2} } = 1$

$\frac{(y - 3)^{2} }{16} + \frac{(x + 4)^{2} }{64} = 1$

7 0

3 years ago

Read 2 more answers

The prism below is made of cubes which measure 1/3 of a centimeter on one side. What is the volume?

Brut [27]

Answer:

the answer is C. 20/27 cubic cm.

Step-by-step explanation:

V = LWH

length 5(1/3 cm)

width 2(1/3 cm)

height 2(1/3 cm)

V = (5/3 cm) (2/3 cm) (2/3 cm)

V = 20/27 cubic cm.

6 0

3 years ago

Read 2 more answers