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Nesterboy [21]
3 years ago
6

On a movie set, an archway is modeled by the equation y = -0.5x2 + 3x, where y is the height in feet and x is the horizontal dis

tance in feet. A laser is directed at the archway at an angle modeled by the equation -0.5x + 2.42y = 7.65 such that the beam crosses the archway at points A and B. At what height from the ground are the points A and B?
Mathematics
1 answer:
tino4ka555 [31]3 years ago
5 0
This question really just needs you to solve the system of equations.  These solutions will be the two points when the curve (archway) and the line (laser) intersect.

Let us express the laser line in terms of y.

-.5x+2.42y=7.65

2.42y=.5x+7.65

y=(.5x+7.65)/2.42

The curve is just y=-.5x^2+3x so when it intersects the curve, y=y and x=x so  we can say:

(.5x+7.65)/2.42=-.5x^2+3x

.5x+7.65=-1.21x^2+7.26x

1.21x^2-6.76x+7.65=0  using the quadratic for simplicity and solving for x:

x=(6.76±√8.6716)/2.42

x≈1.577, 4.010  (to nearest thousandth)

So the heights can found using the simple linear equation y=(.5x+7.65)/2.42 with those values of x...

y≈3.49, 3.99


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The average breaking strength of a certain brand of steel cable is 2000 pounds, with a standard deviation of 100 pounds. A sampl
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Step-by-step explanation:

Things to understand before solving:

  • - <u>Normal Probability Distribution</u>
  1. The z-score formula can be used to solve normal distribution problems. In a set with mean ц and standard deviation б, the z-score of a measure X is given by: Z=\frac{X-u}{a}

The Z-score reflects how far the measure deviates from the mean. After determining the Z-score, we examine the z-score table to determine the p-value associated with this z-score. This p-value represents the likelihood that the measure's value is less than X, or the percentile of X. Subtracting 1 from the p-value yields the likelihood that the measure's value is larger than X.

  • - <u>Central Limit Theorem</u>
  1. The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean ц and standard deviation б , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean ц  and standard deviation s=\frac{a}{\sqrt{n} }

As long as n is more than 30, the Central Limit Theorem may be applied to a skewed variable. A specific kind of steel cable has an average breaking strength of 2000 pounds, with a standard variation of 100 pounds.

This means, ц  = 2000 and б = 100.

A random sample of 20 cables is chosen and tested.

This means that n = 20, s=\frac{100}{\sqrt{120} } =22.361

Determine the sample mean that will exclude the top 95 percent of all size 20 samples drawn from the population.

This is the 100-95th percentile, or X when Z has a p-value of 0.05, or X when Z = -1.645. So Z=\frac{X-u}{a}

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Z=\frac{X-u}{a} \\-1.645=\frac{X-2000}{22.361} \\X-2000=-1.645*22.361

X =1963.2

<h3>Answer:</h3>

The sample mean that will cut off the top 95% of all size 20 samples obtained from the population is 1963.2 pounds.

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