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daser333 [38]
3 years ago
15

Please help me identify the terms and like terms

Mathematics
2 answers:
sergey [27]3 years ago
4 0

Step-by-step explanation:

can you send a new picture I can't see the whole problem

topjm [15]3 years ago
4 0
The terms are (4.2x), (-3.9), (-5.1x), (6)

like terms are terms that represent the same variable.

-3.9 & 6 both do not represent any varibles, they are just numbers, so they are like terms

4.2x & -5.1x both represent (x) so they are like terms.

to collect like terms, you create a smaller equation, just for them.
so you equations are;
-3.9+6
&
4.2x-5.1x

note: you know to add the 6 as all positive numbers have a + infront, it is just not written.

-3.9+6=2.1
4.2x-5.1x=-1.1x

therefore your equation after collecting like terms is 2.1-1.1x.

Hope this helps :)
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Answer:

C

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3 years ago
A company produces birthday cards and get well cards at a ratio of 6 to 5 how many birthday cards can ve expected if 60 get well
Alik [6]

The number of birthday cards made is 72.

<h3>Description of ratios</h3>

Ratio expresses the relationship between two numbers. It shows the frequency of the number of times that one value is contained in another number. The sign used to represent ratios is :

<h3>Determining the total cards made. </h3>

Total card = (sum of ratios x number of get well cards) / ratio of get well cards

(11 x 60) / 5 = 132

<h3>Number of birthday cards made </h3>

6/11 x 132 = 72 cards

To learn more about ratios, please check: brainly.com/question/25927869

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2 years ago
Find, correct to four decimal places, the length of the curve of intersection of the cylinder 4x2 1 y2 − 4 and the plane x 1 y 1
charle [14.2K]

<u>Answer-</u> Length of the curve of intersection is 13.5191 sq.units

<u>Solution-</u>

As the equation of the cylinder is in rectangular for, so we have to convert it into parametric form with

x = cos t, y = 2 sin t   (∵ 4x² + y² = 4 ⇒ 4cos²t + 4sin²t = 4, then it will satisfy the equation)

Then, substituting these values in the plane equation to get the z parameter,

cos t + 2sin t + z = 2

⇒ z = 2 - cos t - 2sin t

∴ \frac{dx}{dt} = -\sin t

  \frac{dy}{dt} = 2 \cos t

  \frac{dz}{dt} = \sin t-2cos t

As it is a full revolution around the original cylinder is from 0 to 2π, so we have to integrate from 0 to 2π

∴ Arc length

= \int_{0}^{2\pi}\sqrt{(\frac{dx}{dt})^{2}+(\frac{dy}{dt})^{2}+(\frac{dz}{dt})^{2}

=\int_{0}^{2\pi}\sqrt{(-\sin t)^{2}+(2\cos t)^{2}+(\sin t-2\cos t)^{2}

=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t)

Now evaluating the integral using calculator,

=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t) = 13.5191




8 0
3 years ago
Nathaniel is making muffins. Each batch uses 2 cups of flour. He plans to use less than 40 cups of flour for muffins so that he
MAXImum [283]

The number of batches Nathaniel can make is 16.5 batches.

Nathaniel plans to make use of less than 40 cups of flour and he has already used 6 cups of flour. In order to determine how many batches he can make, we have to determine the number of cups of flour he can use. The cups of flour would be divided by the amount of flour that can be used to make a batch of muffins.

Maximum amount of flour Nathaniel can use = 39 - 6 = 33

Number of batches he can make = 33 / 2 = 16.5 batches

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8 0
2 years ago
The scale factor from S to M is 3/2 What is the scale factor from M to S
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we conclude that if the scale factor from S to M is 3/2, then the scale factor from M to S is 2/4.

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Suppose we have a figure S. If we apply a stretch of scale factor K to our figure S, we can say that all the dimensions of figure S are multiplied by K.

So, if S represents the length of a bar, then after the stretch we will get a bar of length M, such that:

M = S*K

If that scale factor is 3/2, then we have the case of the problem:

M = (3/2)*S

We can isolate S in the above relation:

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Now we have an equation (similar to the first one) that says that the scale factor from M to S is 2/3.

Then we conclude that if the scale factor from S to M is 3/2, then the scale factor from M to S is 2/4.

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#SPJ1

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