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german
3 years ago
13

Write an equation parallel to y=2x+4 that passes through the point (-2,4)

Mathematics
1 answer:
zysi [14]3 years ago
4 0

Answer:

<u>Answer</u><u>:</u><u> </u><u>y</u><u> </u><u>=</u><u> </u><u>2</u><u>x</u><u> </u><u>+</u><u> </u><u>8</u>

Step-by-step explanation:

• General equation of a line:

\hookrightarrow \: { \rm{y = mx + b}}

  • m is slope / gradient
  • b is y-intercept.

[ for parallel lines, slopes are the same ]

• m is 2

{ \rm{y = 2x + b}}

for point (-2, 4)

{ \rm{4 = (2 \times  - 2) + b}} \\  \\ { \rm{4 =  - 4 + b}} \\  \\ { \rm{b = 8}}

• therefore, equation is:

{ \boxed{ \rm{y = 2x + 8}}}

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To solve problem #1 follow the steps below...

Step 1:Think back to PEMDAS

P=Parentheses
E=Exponents
M=Multiplication
D=Division
A=Addition
S=Subtraction

(Think of M,D as brothers and whichever once comes first in the problem you do.This rule also applies to A,S)

Step 2: Look back to your problem

(6 divided by 2 plus 1) plus 10x2

Step 3: Start with the parentheses

6 divided by 2 plus 1

Step 4: Do the division first

6 divided by 2=3

Step 5:Now the addition

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Step 6: Rewrite the problem

4 plus 10x2

Step 7: Do the multiplication

10x2=20

Step 8: Rewrite your problem again

4 plus 20

Step 9: Solve

4 plus 20=24

Step 10: Look back at your work and see what order your operations were done in

.Division
.Addition
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Step 11: Compare your order to the choices

Answer: b

I hope this helps and if any false information was given I apologize in advance.


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