Question

A collection of dimes is arranged in a triangular array with 17 coins in the base row, 16 in the next, 15 in the next, and so forth. Find the value of the collection.

Answer 1

Answer:

153 coins will be there.

Step-by-step explanation:

The number of coin in the bottom row / or last row = 17

The number of coins in the second last row = 16

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The number of coins in the second row = 2

The number of coins in the first row = 1

So the total number of coins = (Number of coin in the first row) + (Number of coins in the second row) + (Number of coins in the third row) + ....... + (Number of coins in the last row / seventeenth row)

Total number of coins = 1+2+3+....+16+17

Total number of coins = $\frac{17\times(17+1)}{2}=\frac{17\times18}{2}=17\times9=153$

(NOTE: Sum of first n natural number = $\frac{\boldmath n\times(n+1)}{2}$)