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3 years ago

Is it possible to add to negative numbers and get a positive? give reasons for your response

Mathematics

2 answers:

Elodia [21]3 years ago

8 0

Step-by-step explanation:

yes it is possible to get a positive number from adding to a negative number because you can add a -4 + 6 and you'll come out with 2, a positive number anything lower then the negative number across would come out negavie like -4 + -2 comes out as -2 but yes it is possible

Georgia [21]3 years ago

7 0

Yea icdhehurhehwgwgwg

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2 questions! area of plane and composite figures

VikaD [51]

Find the base and height of each side, subtract the triangle from the trapezoid then find the area of the parrellogram and add the subracted one and the obtuse square

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3 years ago

Which graph shows the solution set of the compound inequality 1.5 x minus 1 greater-than 6.5 or 7 x + 3 less-than negative 25

mylen [45]

Answer:

option b

Step-by-step explanation: cause i know it.

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3 years ago

In an effort to estimate the mean amount spent per customer for dinner at a major Atlanta restaurant, data were collected for a

Softa [21]

Answer:

95% Confidence interval = (23.4,26.2)

Step-by-step explanation:

In this problem we have to develop a 95% CI for the mean.

The sample size is n=49, the mean of the sample is M=24.8 and the standard deviation of the population is σ=5.

We know that for a 95% CI, the z-value is 1.96.

The CI is

$M-z*\sigma/\sqrt{n}\leq\mu\leq M+z*\sigma/\sqrt{n}\\\\24.8-1.96*5/\sqrt{49}\leq\mu\leq 24.8+1.96*5/\sqrt{49}\\\\ 24.8-1.4\leq\mu\leq 24.8+1.4\\\\23.4\leq\mu\leq 26.2$

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4 years ago

Help me guys <br> thx so much

navik [9.2K]

Answer:

Option D, $10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}$

Step-by-step explanation:

<u>Step 1: Multiply</u>

<u /> $(\sqrt{10x^4} -x\sqrt{5x^2} )*(2\sqrt{15x^4} + \sqrt{3x^3})\\ (\sqrt{10 * x^2 * x^2} -x\sqrt{5 * x^2} ) * (2\sqrt{15 * x^2 * x^2} +\sqrt{3 * x^2 * x})\\(x^2\sqrt{10} -x^2\sqrt{5} )*(2x^2\sqrt{15} +x\sqrt{3x}) \\\\$

$(x^2\sqrt{10}*2x^2\sqrt{15} )+(x^2\sqrt{10}*x\sqrt{3x} ) + (-x^2\sqrt{5} *2x^2\sqrt{15}) + (-x^2\sqrt{5} *x\sqrt{3x}$

$(2x^4\sqrt{150} ) + (x^3\sqrt{30x}) + (-2x^4\sqrt{75}) + (-x^3\sqrt{15x} )$

$2x^4\sqrt{5^2*6} + x^3\sqrt{30x} -2x^4\sqrt{5^2*3} -x^3\sqrt{15x}$

$10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}$

Answer: Option D, $10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}$

6 0

4 years ago

Read 2 more answers

A pile of sand in the shape of a cone has a diameter of 8 in. and a height of 5 in.

max2010maxim [7]

if it has a diameter of 8, that means its radius is half that, or 4.

$\bf \textit{volume of a cone}\\\\
V=\cfrac{\pi r^2 h}{3}~~
\begin{cases}
r=radius\\
h=height\\[-0.5em]
\hrulefill\\
r=4\\
h=5
\end{cases}\implies V=\cfrac{\pi (4)^2(5)}{3}\implies V=\cfrac{80\pi }{3}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
~\hfill \stackrel{using~\pi =3.14}{V= 83.7\overline{3}}~\hfill$

8 0

3 years ago