The way to do it can be explained like this:
Say AB and CD are the two parallel lines cut by a transversal at E and F respectively.
Then the pairs of alternate interior angles are:
Angle(AEF) and Angle(DFE)
Angle(CFE) and Angle(BEF)
Now lets prove if this is true:
<span>Angle(CFE) +Angle(DFE) = 180
(linear pair)
Also
Angle(CFE) +Angle(AEF) = 180
(Corresponding angles)
</span><span>Equate the above results:
Angle(CFE) +Angle(DFE) = Angle(CFE) +Angle(AEF)
</span><span>Angle(DFE) = Angle(AEF)
</span>Happens the same with
<span>Angle(CFE) = Angle(BEF)
</span>Hope this is very useful for you
Keywords:
<em>Product, factors, polynomial, distributive property
</em>
For this case we must find the product of two factors of a polynomial. To do this, we must apply the distributive property, which states:
So:
Thus, the product of is:
Answer:
The product of is:
Answer:
Yes, the triangles are simirar with a scale factor of 3/2.
Step-by-step explanation:
We find the scale factor by dividing corresponding sides:
12/8=3/2
18/12=3/2
24/16=3/2
An inscribed angle (BAC) is one half the angle of a central angle (BOC) that intercepts the same arc. Therefore, BAC = 34 degrees.