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astraxan [27]
3 years ago
14

Find the remainder for (x^10 + x^9 +...+x+1) divided by (x^2 - 1)

Mathematics
1 answer:
Assoli18 [71]3 years ago
3 0

Since x^2-1=(x-1)(x+1), by the remainder theorem we have

\dfrac{p(x)}{x-1} = q(x) + \dfrac{p(1)}{x-1} = q(x) + \dfrac{11}{x-1}

where p(x) = x^{10}+x^9+\cdots+x+1.

Then

\dfrac{p(x)}{x^2-1} = q^*(x) + \dfrac{q(-1)}{x+1} + \dfrac{11}{x^2-1} = q^*(x) + \dfrac{q(-1)(x-1) + 11}{x^2-1}

The only missing piece is <em>q(x)</em>, which we can get through usual polynomial division:

\dfrac{x^{10}+x^9+\cdots+x+1}{x-1} = \underbrace{x^9 + 2x^8 + 3x^7 + \cdots + 9x + 10}_{q(x)} + \dfrac{11}{x-1}

so that

q(-1) = (-1)^9 + 2(-1)^8 + \cdots + 9(-1) + 10 = 5

Then the remainder we want is

\dfrac{p(x)}{x^2-1} = q^*(x) + \dfrac5{x+1} + \dfrac{11}{x^2-1} = q^*(x) + \dfrac{5(x-1)+11}{x^2-1} = q^*(x) + \dfrac{\boxed{5x+6}}{x^2-1}

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7 0
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I need the volume for 9,11,and 13
mihalych1998 [28]

Hey there!

<h3>Question 1</h3>

Let's use 3.14 for pi during this. It'll make it a lot easier.

The volume for a cone is \pi r^{2} \frac{h}{3}.

The diameter of this cone is 17.6 inches. Since the radius is half the diameter, we can find the radius by dividing this amount by 2.

17.6 ÷ 2 = 8.8

The height of this cone is 23.4 inches.

Plug the values into the equation.

\pi 8.8^{2} \frac{23.4}{3}

Next, square 6.8 and divide 23.4 by 3. Also, replace the pi symbol with 3.14.

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Multiply the numbers together.

<u>The volume of this cone is approximately 1896.66 cubic inches.</u>

<h3>Question 2</h3>

Finding the volume of a trapezoidal prism can be done by finding the are of the trapezoidal face and multiplying it by the depth.

Formula for finding the area of a trapezoid is a = \frac{1}{2} h(b_{1} +b_{2} )

The two bases are 10 and 34, and the height is 24.7 feet. Put these values into the equation.

a = \frac{1}{2} 24.7(10 +34 )

Add 10 and 34, then multiply it by 24.7 and 1/2.

a = 543.4

Multiply that value by 19, which is the depth of the figure.

<u>The volume of the prism is 10324.6 cubic feet.</u>

<h3>Question 3</h3>

The formula for volume of a triangular pyramid is v = 1/3ah, with a the area of the base and h the height.

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The length of the side is 12, so we can square that to get 144.

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The area of the base is about 62.35 square meters.

The height of the pyramid is 20 meters. Plug that and the area of the base into the equation.

v = 1/3 x 62.35 x 20

Multiply the numbers together to get the volume.

<u>The volume of the pyramid is approximately 415.67 cubic meters.</u>

Hope this helps!

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is                    x           140

----   SO ...    -------  =  --------

of                  60         100

(hit like pls)

60*140=100x

8400=100x

/100     /100

-------------------

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