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3 years ago

Can someone please help me?

Mathematics

1 answer:

storchak [24]3 years ago

6 0

5lbs=8.25
/5 /5
1lbs=1.65

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Someone smart help me please

mafiozo [28]

Pretty sure it is
shift 1 left
i might be wrong

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3 years ago

Tickets for a concert cost $29. 00. The greatest number of tickets one person can buy is 9.If 28 peopleeach buy 9 tickets for $2

Blababa [14]

Answer: 7,308

Step-by-step explanation: 28 X 9 = 252

252 X 29 = 7,308

6 0

3 years ago

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Sorry my brain hurts... Most of u love the points anyway

Amanda [17]

I think the answer's C: $7000/$8000
That's a surprisingly easy question for high school

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3 years ago

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Solve for v<br> 5v-13=67

borishaifa [10]

Answer:

Step-by-step explanation:

Add 13 both sides

That would give you 5v=80

Divide 80 by 5. So v would equal 16

8 0

3 years ago

The average score of all pro golfers for a particular course has a mean of 70 and a standard deviation of 3.0 (Think of these as

bija089 [108]

Answer:

0.477 is the probability that the average score of the 36 golfers was between 70 and 71.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 70

Standard Deviation, σ = 3

Sample size, n = 36

Let the average score of all pro golfers follow a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(score of the 36 golfers was between 70 and 71)

$\text{Standard error of sampling} = \displaystyle\frac{\sigma}{\sqrt{n}} = \frac{3}{\sqrt{36}} = \frac{1}{2}$

$P(70 \leq x \leq 71) = P(\displaystyle\frac{70 - 70}{\frac{3}{\sqrt{36}}} \leq z \leq \displaystyle\frac{71-70}{\frac{3}{\sqrt{36}}}) = P(0 \leq z \leq 2)\\\\= P(z \leq 2) - P(z \leq 0)\\= 0.977 - 0.500 = 0.477= 47.7\%$

$P(70 \leq x \leq 71) = 47.7\%$

0.477 is the probability that the average score of the 36 golfers was between 70 and 71.

8 0

3 years ago