First, I'm going to separate factor the expression inside of the square root.
sqrt[ (2/18) * (x^5) ]
sqrt[ (1/9) * (x^5) ]
We can take the square root of 1/9 easily, because 1 and 9 are both perfect squares. The square root of 1/9 is 1/3.
Looking at the x^5, we can separate it into x^2 * x^2 * x^1. The square root of x^2 is x. So, we now also have an x^2 on the outside because there are two x^2s in our expanded form.
ANSWER: (x^2 * sqrt(x)) / 3
(Option 1)
Hope this helps!
Answer:
No, 6 is not a solution to the equation x2-4=5x
Step-by-step explanation:
6(2)-4=5(6)
12-4=30
8=30
The question is basically asking if you replace x with 6, will the equation equal each other on both sides, for example 6=6 or 3.5=3 1/2. In this case the equation gives us 8=30 which means 6 would not be a solution since both sides aren't equal to one another, 30 is bigger than 8.
