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Cerrena [4.2K]
2 years ago
11

Put me out of my misery! Help me! If possible could you show me how to do this?

Mathematics
2 answers:
prisoha [69]2 years ago
8 0

Answer:

4

4z+4

​

Divide each term of 4z+4 by 4 to get 1+z.

1+z

seraphim [82]2 years ago
3 0

Answer:

Your answer is going to be 4z + 1

Step-by-step explanation:

first, you're going to divide the numbers

4z + 4/4 then turn it into 4z + 1 and there is your answer.

Hope this helps!

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Ms. Larson was driving home from a vacation. At noon, she was 120 miles from home. Half an hour later, she was 98 miles from hom
melomori [17]

Answer: her speed was “44 miles per hour”

5 0
2 years ago
Please help Use the expression 8a + 16c.
alexdok [17]

Answer:

C  89a + 2c)

Step-by-step explanation:

The largest factor of both 8 and 16 is 8.  So, 8 = GCF

factor out an 8 and you get 8(a + 2c)

To check if you are correct, multiply and see if you get what you started with.

3 0
3 years ago
Read 2 more answers
Help me on this question..........
aleksandrvk [35]
Answer: $18





Explanation: 6x3



7 0
3 years ago
If a cannonball is shot directly upward with a velocity of 160 ft per​ second, its height above the ground after t seconds is gi
Contact [7]

Step-by-step explanation:

If a cannonball is shot directly upward with a velocity of 160 ft per​ second. Its height as a function of time is given by :

h(t)=160t-16t^2 .......(1)

t is in seconds

(a) Velocity is given by :

v=\dfrac{dh}{dt}\\\\v=\dfrac{d(160t-16t^2)}{dt}\\\\v=(160-32t)\ ft/s  

Acceleration is given by :

a=\dfrac{dv}{dt}\\\\a=\dfrac{d(160-32t)}{dt}\\\\a=-32\ ft/s^2

(b) For maximum height put \dfrac{dh}{dt}=0

i.e.

160-32t=0\\\\t=5\ s

Put t = 5 s in equation (1). So,

h(5)=160t-16t^2\\\\h(5)=160(5)-16(5)^2\\\\h(5)=400\ ft

(c) When the ball reaches ground, its height is equal to 0. So,

h(t) = 0

160t-16t^2=0\\\\t(160-16t)=0\\\\t=0,t=10\ s

Hence, this is the required solution.

4 0
3 years ago
I really need help with 15 and 16 please
Mandarinka [93]

Answer:

  15. 50 kg

  16a. 5 kg

  16b. 3.75 kg

Step-by-step explanation:

The formula relating force, mass, and acceleration can be solved for mass. This formula will apply to both problems. We'll use m for both "mass" and "meters". We presume you can avoid getting mixed up by understanding that meters is used in the context of acceleration: m/s².

  F = ma

  m = F/a . . . . . divide by a

__

15. m = (250 N)/(5 m/s²) = 50 kg

__

16a. m = (15 N)/(3 m/s²) = 5 kg

16b. m = (15 N)/(4 m/s²) = 3.75 kg

_____

<em>Comment on units</em>

Especially for physics problems, I like to keep the units with the numbers. It is helpful to remember that Newtons are equivalent to kg·m/s². So, dividing Newtons by acceleration in m/s² will give mass in kg. Since you're familiar with F=ma, it's not too hard to remember that the units of force (N) are the product of the units of mass (kg) and acceleration (m/s²).

6 0
3 years ago
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