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MakcuM [25]
3 years ago
10

Can someone please help me I don’t understand what to do

Mathematics
1 answer:
Soloha48 [4]3 years ago
6 0
So angle 4 and angle 2 are gonna equal 180

So your equation should say

3x - 10 + 70 = 180
3x + 60 = 180
-60 -60
3x = 120
— —
3 3
X = 40

And your answers x = 40
Hope you understood
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Use an online math calculator for more accurate answers just plug in the variables
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2 years ago
A swimming pool has a diameter of 24 feet. What is the minimum amount of fabric needed to cover the pool if the cover must hang
Alika [10]

Answer:

531.167 ft²

Step-by-step explanation:

Given data

Dimension of pool

Diameter =24ft

Radius =12ft

If the cover must hang by 1ft around, then the diameter is 26ft

Radius =13ft

Area of cover = πr²

Substitute

Area = 3.142*13²

Area =3.143*169

Area =531.167 ft²

Hence the minimum area is 531.167 ft²

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3 years ago
Of the following numbers, which one is prime: 14, 13, 21, 33?
Dvinal [7]
13 is a prime number because you can't multiply 2 numbers to make 13
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4 years ago
Consider the following graph
DENIUS [597]

a) The equation of axis is the middle y-coordinate, which is y = -1.5.

b) The period is the amount of time it takes for the graph to repeat, which is 6.

c) The amplitude is the vertical distance from an extreme point to the midpoint, which is 3.

d) This is a cosine graph since when x=0, y is not equal to 0.

7 0
2 years ago
Activity
Sergio039 [100]

Answer:

A:

Dylan’s weight is d.

Twice Dylan’s weight is 2d.

Three pounds more than twice Dylan’s weight is 2d + 3.

So, the expression for Alan’s weight in terms of Dylan’s weight is 2d + 3.

B:

Dylan’s weight is d.

Three times Dylan’s weight is 3d.

Twelve less than three times Dylan’s weight is 3d − 12.

So, the expression for Bruce’s weight in terms of Dylan’s weight is 3d − 12.

C:

Cecil’s weight is the sum of Alan's weight and Bruce's weight.

Alan’s weight in terms of Dylan's weight is 2d + 3.

Bruce’s weight in terms of Dylan's weight is 3d − 12.

So, the expression for Cecil’s weight in terms of Dylan’s weight is (2d + 3) + (3d − 12).

D:

Cecil's weight is (2d + 3) + (3d − 12).

Find Cecil's weight by substituting Dylan’s weight (d = 45) into the expression above:

(2 × 45 + 3) + (3 × 45 − 12)

=  (90 + 3) + (135 − 12)

=  93 + 123

=  216.

If Dylan weighs 45 pounds, then Cecil weighs 216 pounds.

E:

Yes, the expression can be simplified by using the Associative and Commutative Properties of addition and by combining the like terms in the expression.

F:

(2d + 3) + (3d − 12)

First remove the parentheses:

2d + 3 + 3d − 12.

Then group the like terms:

2d + 3d + 3 − 12.

Finally, add and subtract the like terms:

5d − 9.

The expression (2d + 3) + (3d − 12) simplifies to 5d − 9.

G:

Cecil’s weight in terms of Dylan’s weight is 5d – 9.

Find Cecil’s weight by substituting Dylan’s weight (d = 45) into the expression above:

(5 × 45) − 9

= 225 − 9

= 216.

If Dylan weighs 45 pounds, then Cecil weighs 216 pounds.

H:

Yes, the answers are the same. The expression from part D is equivalent to the expression from part G.

I:

Bruce's weight in terms of Dylan’s weight is 3d − 12.

Alan's weight in terms of Dylan’s weight is 2d + 3.

So, the expression (3d − 12) − (2d + 3) represents how much more Bruce weighs than Alan.

J:

The expression is (3d − 12) − (2d + 3).

Evaluate the expression by substituting Dylan’s weight (d = 45) into it:

(3 × 45 − 12) − (2 × 45 + 3)

= (135 − 12) − (90 + 3)

= (123) − (93)

= 30.

Bruce weighs 30 pounds more than Alan weighs.

K:

The expression (3d − 12) − (2d + 3) simplifies to d − 15.

L:

The expression is d − 15.

Evaluate the expression by substituting Dylan’s weight (d = 45) into it:

45 − 15 = 30.

Bruce weighs 30 pounds more than Alan. This is the same answer as in part J.

Do not copy, it's the exact answer from edmuentum

5 0
3 years ago
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