All categories

3 years ago

Please help I really need this!

Mathematics

1 answer:

Rus_ich [418]3 years ago

6 0

Mark me brainliest plsssssss

You might be interested in

A pack of four CFL bulbs cost $5.12 what is the cost for CFL bulb HELPPP MEHHH BTW ADD ME ON FORTNITE poineytail360

OverLord2011 [107]

$1.28

If you divide $5.12 by 4 you get 1.28

so it's 1.28 per

3 0

3 years ago

Given b(x)=√3x+3 evaluate f(11) I really need help with this.

andre [41]

Step-by-step explanation:

$\huge{\purple{\underline{\underline{\bf{\pink{Answer}}}}}}$

in we have x = 11

put the value of x in equation

$b(11) = \sqrt{3} (11) + 3$

$b(11) = 11 \sqrt{3} + 3$

so x = 11√3

Hope it helps

4 0

4 years ago

Given the function f(x) = -5x2 +4, what is the value of f(-5)?

Akimi4 [234]

Step-by-step explanation:

f(-5)=-5(-5)²+4

f(-5)=5(25)+4

f(-5)=125+4

f(-5)=129

8 0

3 years ago

HELP ME PLEASE!!!!!!!

kotegsom [21]

Answer:

1. (0,0) (3,1) (6,2)

2. proportinal

3. im so sorry but i cant see that one i really am sorry!

Step-by-step explanation:

i hope i helped brainliest?

3 0

3 years ago

According to industry sources, online banking is expected to take off in the near future. The projected number of households (in

Airida [17]

Answer:

(a) The least-square regression line is: $y=4.662+2.709x$ .

(b) The number of households using online banking at the beginning of 2007 is 31.8.

Step-by-step explanation:

The general form of a least square regression line is:

$y=\alpha +\beta x$

Here,

y = dependent variable

x = independent variable

α = intercept

β = slope

(a)

The formula to compute intercept and slope is:

$\begin{aligned} \alpha &= \frac{\sum{Y} \cdot \sum{X^2} - \sum{X} \cdot \sum{XY} }{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} \\\beta &= \frac{ n \cdot \sum{XY} - \sum{X} \cdot \sum{Y}}{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} \end{aligned}$

The values of ∑X, ∑Y, ∑XY and ∑X² are computed in the table below.

Compute the value of intercept and slope as follows:

$\begin{aligned} \alpha &= \frac{\sum{Y} \cdot \sum{X^2} - \sum{X} \cdot \sum{XY} }{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} = \frac{ 68.6 \cdot 55 - 15 \cdot 218.9}{ 6 \cdot 55 - 15^2} \approx 4.662 \\ \\\beta &= \frac{ n \cdot \sum{XY} - \sum{X} \cdot \sum{Y}}{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} = \frac{ 6 \cdot 218.9 - 15 \cdot 68.6 }{ 6 \cdot 55 - \left( 15 \right)^2} \approx 2.709\end{aligned}$

The least-square regression line is:

$y=4.662+2.709x$

(b)

For the year 2007 the value of x is 10.

Compute the value of y for x = 10 as follows:

$y=4.662+2.709x$

$=4.662+(2.709\times10)\\=4.662+27.09\\=31.752\\\approx 31.8$

Thus, the number of households using online banking at the beginning of 2007 is 31.8.

5 0

3 years ago