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Inga [223]
3 years ago
6

A cereal box is labeled as containing 16 ounces. Suppose the production line manager tests to determine whether the average weig

ht of cereal in a box is less than 16 ounces. He concludes that the null hypothesis should not be rejected. Which of the following is a correct statement?(A) The production line appears to be filling the cereal boxes with at least 16 ounces of cereal. (B) The weights in each box must have been recorded incorrectly. (C) The company should either change the label or add more cereal to each box in the production line. (D) No conclusions regarding the weight of cereal in a box can be drawn from the test.
Mathematics
1 answer:
meriva3 years ago
7 0

Answer:

Lyrics A

Step-by-step explanation:

Problem statement does not  mention anything about conditions of the test, so we dont know if the experiment was correctly done, but we know the kind of problem we are facing here is concerning a normal distribution

Then assuming the test was done by knowledgeable  people, which means:

- they got correct information from the population

-sample was big enough

- level of confidence was acceptable for the test ( approximately 95 %)         - Alternative hypothesis took into account two tails test

-Test was evaluated according to sample size

-And finally calculations were right

Under the above mentioned conditions, they  tested  the hypotesis  H₀ = μ₀ = 16 ounces and they got results that implies the acceptance of such hypothesis (that means the null hypothesis should not be rejected), and the answer is lyrics A

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Tristan is comparing two number patterns based on the information below.
ivanzaharov [21]

Answer:

Pattern B gets larger fast since 4 is greater than 3.

explanation:
Pattern A is ; 1, 4, 7, 10, 13

Pattern B: 1, 5, 9, 13, 17

as u can see pattern b goes up faster

8 0
2 years ago
Let X denote the data transfer time (ms) in a grid computing system (the time required for data transfer) between a "worker" com
My name is Ann [436]

Answer:

a. The value of alpha is 3.014 and the value of beta is 12.442

b. The probability that data transfer time exceeds 50ms is 0.238

c. The probability that data transfer time is between 50 and 75 ms is 0.176

Step-by-step explanation:

a. According to the given data we have that the mean and standard deviation of the random variable X are 37.5 ms and 21.6.

Therefore, E(X)=37.5 and V(X)=(21.6)∧2  

To calculate alpha we would have to use the following formula:

alpha=E(X)∧2/V(X)

alpha=(37.5)∧2/21.6∧2

alpha=1,406.25 /466.56

​alpha=3.014

To calculate beta we would have to use the following formula:

β=  V(X) ∧2/E(X)

β=(21.6)  ∧2/37.5

β=466.56 /37.5

β=12.442

b. E(X)=37.5 and V(X)=(21.6)∧2  

Therefore, P(X>50)=1−P(X≤50)

Hence, To calculate the probability that data transfer time exceeds 50ms we use the following formula:

P(X>50)=1−P(X≤50)

=1−0.762

=0.238

The probability that data transfer time exceeds 50ms is 0.238

c. E(X)=37.5 and V(X)=(21.6)∧2  

​Therefore, P(50<X<75)=P(X<75)−P(X<50)  

Hence, To calculate the probability that data transfer time is between 50 and 75 ms we use the following formula:

P(50<X<75)=P(X<75)−P(X<50)

=0.938−0.762

=0.176

​

The probability that data transfer time is between 50 and 75 ms is 0.176

6 0
3 years ago
The diagonals of a rectangle ABCD meet at O if AO=(2x+3)cm and DO=(5x)cm find the length of its diagonals also find the perimete
vfiekz [6]

Step-by-step explanation:

AO = DO

2x+3 = 5x

3 = 5x-2x

3 = 3x

x = 1

DO = 5(1)=5cm

AC = 2×5 = 10cm

BC =√10²-8²

= √100-64

=√36

=6 cm

therefore, the perimeter of the rectangle

= 2×(8+6) = 2(14) = 28 cm

3 0
2 years ago
Solve.
lions [1.4K]

Answer:

b=9,a=12

Step-by-step explanation:

I solved by substitution:

b = 3/4a  ---> plug this into the other equation

a + b = 21   is now    a + 3/4a = 21

Reduce: 7/4a = 21

a = 12

Now solve for b:

b=3/4a is now b=3/4(12)

b=9

6 0
3 years ago
Read 2 more answers
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Softa [21]

Answer:

6 hours.

Step-by-step explanation:

5/6 / 5 is 1/6. 6 divided by 1 out of 6 is 6. so 6 hours

3 0
3 years ago
Read 2 more answers
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