2 years ago

{(-1, 2), (0, 2), (5, 2)} is a function.

Mathematics

1 answer:

gayaneshka [121]2 years ago

4 0

The relation is a function.

Step-by-step explanation:

As there is only one y-value for every x-value, this is a function

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Surely help I’ll brainlist.<br><br> construct a histogram to represent these results.

AnnZ [28]

Answer:

Step-by-step explanation:

You need to first put the numbers in suitable catagories

0-120

120-130

130-140

140-150

then figure out the frequency of them

0-120=4

121-130=20

131-140=2

141-150=2

then put in a graph(sry its not very good i was in a rush)

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2 years ago

divide the number 120 into three parts such that the first and second are twice and three times the third respectively HELP MEEE

Misha Larkins [42]

Answer:

Step-by-step explanation:

Step by step:

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3 years ago

Hey can you please help me posted picture of question :)

scoray [572]

X^2-7x+38=5x+3
x^2-7x+38-5x-3=5x+3-5x-3
x^2-12x+35=0
Factoring:
(x-5)(x-7)=0
Two solutions:
x-5=0→x-5+5=0+5→x=5
x-7=0→x-7+7=0+7→x=7
Answer: x=5 and x=7

Answer: Options B. 7 and D. 5

3 0

3 years ago

Read 2 more answers

Suppose that the functions g and h are defined for all real numbers r as follows. gx) -4x +5 h (x) = 6x write the expressions fo

aleksandr82 [10.1K]

Answer: Our required values would be -10x+5, 2x+5 and -25.

Step-by-step explanation:

Since we have given that

g(x) = -4x+5

and

h(x) = 6x

We need to find (g-h)(x) and (g+h)(x).

So, (g-h)(x) is given by

$g(x)-h(x)\\\\=-4x+5-6x\\\\=-10x+5$

and (g+h)(x) is given by

$g(x)+h(x)\\\\=-4x+5+6x\\\\=2x+5$

and (g-h)(3) is given by

$-10(3)+5\\\\=-30+5\\\\=-25$

Hence, our required values would be -10x+5, 2x+5 and -25.

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3 years ago

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swat32

Yes that is correct. And?

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4 years ago