For a cyclic quadrilateral
The opposite angles are supplementary (meaning they sum up to 180 °)
I.e (x +20) ° + 3x ° =180 °
20 + 4x = 180
4x=180 - 20
4x = 160
Divide through by 4
x = 40 °
Angle at point A
(2x + 38) = (2(40) + 38) = 118 °
Angle at point B
3x = 3(40) = 120 °
Angle at point D
x + 20 = 40 + 20 = 60 °
Angle at point C
The total angle in a quadrilateral is 360 °
I.e 118 + 120 + 298 +
To get the box plot we begin by arranging the data in ascending order:
<span>135, 149, 156, 112, 134, 141, 154, 116, 134, 156
rearranging we get:
112,116, 134, 134, 135, 141, 149, 154, 156, 156
then:
Lower value=112
Q1=134
Median=(135+141)/2=138
Q3=154
Largest value=156
The second figure is the correct figure.
</span>
Answer:
30,000,000
Step-by-step explanation:
Hope this helps!
Answer:
1) (x + 12)²+(y+6)²= 28
comparing above equation with(x-h)²+(y-k)²=r²
we get
r=√28
h=-12
k=-6
;.centre=(-12,-6)
radius =√28 units
2) x²+(y+7)²=15
comparing above equation with(x-h)²+(y-k)²=r²
we get
r=√15
h=0
k=-7
;.centre=(0,-7)
radius=√15 units
3) (x + 4)²+(y - 1)² = 4
comparing above equation with(x-h)²+(y-k)²=r²
we get
r=√4=2units
h=-4
k=1
;.centre=(-4,1)
radius=√2units
4) (x+3)²+(y-1)²= 8
comparing above equation with(x-h)²+(y-k)²=r²
we get
r=√8=2√2units
h=-3
k=1
;.centre=(-3,1)
radius=2√2units
