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fomenos
3 years ago
6

What value of x makes the equation true?

Mathematics
2 answers:
Vedmedyk [2.9K]3 years ago
7 0

Answer:

a=33

Step-by-step explanation:

simplify each term until you get to the bottom! hope this helped !

Inessa05 [86]3 years ago
7 0
<h2><u>Answer:</u></h2><h2><u></u>\boxed{\boxed{\sf{a=33}}}<u></u></h2><h2><u></u></h2><h2><u>Solution Steps:</u></h2>

______________________________

<h3>1.) Rewrite:</h3>
  • 4-(2a+3)=-3(a-1)+31 turns into 4-2a-3=-3(a-1)+31

<em>  - The </em>(2a+3)<em> turns into </em>2a-3<em> because you have to find the opposite or the terms. So this just means, if something is positive: it turns negative, and if something it negative: it turns positive.  </em>

<u>Equation at the end of Step 1:</u>

  • <u />4-2a-3=-3(a-1)+31<u />
<h3><em /></h3><h3>2.) Subtract 3 on both sides, (Right Side):</h3>
  • -3-3= Cancels Out
  • 4-3=1

<em>  - We do this to get rid of/cancel out the 3. Since when we get to the equation we need 1 number and variable so to do this, you just do the opposite of what you see. In this case the 3 is positive, so you subtract 3 on each side. However you only subtract the 3 on the right side.</em>

<u>Equation at the end of Step 2:</u>

  • <u />1-2a=-3(a-1)+31<u />

<em />

<h3>3.) Use the distributive property to multiply −3 by a−1:</h3>
  • -3 × a=-3a
  • -3 × -1=3

<em>  - We do this because we need to make the Left side smaller, and since there are parenthesis you must do them first. So with parenthesis you just multiply the numbers/variables by the outside number/variable. </em>

<u>Equation at the end of Step 3:</u>

  • <u />1-2a=-3a+3+31<u />
<h3 /><h3>4.) Add 3 and 31:</h3>
  • 3+31=34

<em>  - We do this since both numbers don't have any variables attached to them, you can just combine them by adding. </em>

<u>Equation at the end of Step 4:</u>

  • <u />1-2a=-3a+34<u />
<h3><em /></h3><h3>5.) Add 3a to both sides:</h3>
  • -3a+3a= Cancels Out
  • -2a+3a=a

<em>  - We do this because you only need 1 variable at the end of the equation, so to get the 1, you just combine them. </em>

<u>Equation at the end of Step 5:</u>

  • <u />1+a=34<u />
<h3><em /></h3><h3>6.) Subtract 1 from both sides:</h3>
  • 1-1= Cancels Out
  • 34-1=33

<em>  - We do this to get 1 number and variable left. To do so you do the opposite of what you see: In this case we have a positive 1, so you subtract 1 on each side. </em>

<em />

So your answer is \bold{a=33}.

______________________________

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