10

Can someone help me please

Margarita [4]

Answer:

46

Step-by-step explanation:

Solution :

Remember that the sum of complementary angles is always 90°.

First, finding the value of x :

Set up an equation :

( Being complementary angles )

Solve for x

{ Remove unnecessary parentheses }

{ Combine like terms }

{ Subtract 3 from 30 }

{ Move 27 to right hand side and change it's sign }

{ Subtract 27 from 90}

{ Divide both sides by 9 }

The value of X is 7°

Now, Replacing the value of x in order to find the value of B

{ Plug the value of x }

{ Multiply 7 by 7 }

{ Subtract 3 from 49 }

The measure of B is 46°

7 0

3 years ago

A cigarette industry spokesperson remarks that current levels of tar are no more than 5 milligrams per cigarette. A reporter doe

d1i1m1o1n [39]

Answer:

$t=\frac{5.63-5}{\frac{1.61}{\sqrt{15}}}=1.516$

$df=n-1=15-1=14$

Since is a right tailed test the p value would be:

$p_v =P(t_{14}>1.516)=0.076$

If we use a significance level of 0.05 we see that $p_v > \alpha$ and then we can conclude that we don't have evidence in order to conclude that the mean is higher than 5.63, so then the claim makes sense.

Step-by-step explanation:

Data given and notation

$\bar X=5.63$ represent the sample mean

$s=1.61$ represent the standard deviation for the sample

$n=15$ sample size

$\mu_o =15/tex] represent the value that we want to test 
[tex]\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses to be tested

We need to conduct a hypothesis in order to determine if the average is more than 5.63, the system of hypothesis would be:

Null hypothesis: $\mu \leq 5.63$

Alternative hypothesis: $\mu > 5.63$

Compute the test statistic

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

We can replace in formula (1) the info given like this:

$t=\frac{5.63-5}{\frac{1.61}{\sqrt{15}}}=1.516$

Now we need to find the degrees of freedom for the t distribution given by:

$df=n-1=15-1=14$

P value

Since is a right tailed test the p value would be:

$p_v =P(t_{14}>1.516)=0.076$

If we use a significance level of 0.05 we see that $p_v > \alpha$ and then we can conclude that we don't have evidence in order to conclude that the mean is higher than 5.63, so then the claim makes sense.

3 0

3 years ago

Factor p^2-q^2-2p+2q

Grace [21]

Not sure of the answer but i know what factors
p ^2 - 2p

p (p-2)

-q^2 +2q

-q (q-2)

so maybe (p-q) (p-2) (q-2)

6 0

3 years ago

Read 2 more answers

What is 1/10 of 1000

Marianna [84]

It is 100. There is many ways to find this answer. One way would be to divide 1000 by 10 to get a 100. Another way is to take the decimal form of 1/10 which is .10 and times it by 1000 to get 100.

4 0

3 years ago

Read 2 more answers

Tamika has two bags of trail mix. Each has a combination of 60 pieces of fruit and nuts. Ratio of fruit to nuts in the first bag

madam [21]

Answer:

the second bag because the ratio is greater

Step-by-step explanation:

Bag1

fruits 3 : 5 nuts so 3+5=8 and 60/8=7.5 but 7.5*3=22.5

ratio is 3/5=0.428

Bag2

fruits 7 : 10 nuts so 10+7=17 and (60/17)*7 ≈ 24.7

ratio is 7/10=0.7

4 0

3 years ago

Read 2 more answers