Answer:
The father is 50 and his son is 15.
Step-by-step explanation:
Double the tens digit of the father's age = 10
Plus 5 = 15 (the age of the son)
50 + 15 = 65 (the sum of their ages)
The reverse of the digits of the son's age is 51.
Subtract 1 = 50 (the age of the father)
Answer:
Bag 1: 20
Bag 2: 40
Step-by-step explanation:
Let x be the amount taken out of bag 2
Then the amount left in each bag can be written as:
Bag 1: 50-3x
Bag 2: 50-x
Since we know that half of bag 2 is bag 1, that gives us:
50-3x = 1/2(50-x)
-> 50-3x = 25-x/2
Now lets isolate x and solve:
25 = 5x/2
-> 50 = 5x
-> x = 10
So plug x bag in for the original equations:
Bag 1: 50-3x = 50-3(10) = 20
Bag 2: 50-x = 50-10 = 40
Answer:
x = 5
Step-by-step explanation:
11 = 4x-9
20 = 4x
20/4 = 4x/4
5 = x