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inna [77]
2 years ago
6

3-17. The question is in bold

Mathematics
1 answer:
MissTica2 years ago
6 0

Answer:

-14

Step-by-step explanation:

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Write a quadratic function in vertex form whose graph has the vertex (5,−2) and passes through the point (7,0).
Hatshy [7]

The quadratic function in vertex form is y=\frac{1}{2} (x-5)^{2}-2.

Solution:

The equation of a quadratic in  vertex form  is y=a(x-h)^{2}+k.

where  (h, k) are the coordinates of the vertex and "a"  is a multiplier.

Here (h, k) = (5, –2)

Substitute this in the vertex form.

y=a(x-5)^{2}+(-2)

y=a(x-5)^{2}-2 – – – – (1)

Passes through the point (7, 0).

Here x = 7 and y = 0.

Substitute this in equation (1), we get

0=a(7-5)^{2}-2

0=4a-2

Add 2 on both sides.

2 = 4a

Divide 2 on both sides, we get

$a=\frac{1}{2}

Substitute the value of a in equation (1),

$y=\frac{1}{2} (x-5)^{2}-2

The quadratic function in vertex form is y=\frac{1}{2} (x-5)^{2}-2.

8 0
3 years ago
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Alchen [17]
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6x + 12 = -5y<br> Is this question in standard form?? Why or why not??? Please help me!!
DiKsa [7]

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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