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2 years ago

PLZ HELP MEH FOR A BUNCH O POINTS PLLLLLLZZZZZZZZZ I NEED NUMBER 2 BASED ON NUMBER 1!!!!!!

Mathematics

2 answers:

aleksandrvk [35]2 years ago

3 0

Answer:

Step-by-step explanation:

nataly862011 [7]2 years ago

3 0

Answer:

$93.56

Step-by-step explanation:

93.56 / 4 = 23.39

So each person needs to pay $23.39.

<h2><u><em>PLEASE MARK AS BRAINLIEST!!!!!</em></u></h2>

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Each person in ellens family drinks 8 1/3 ounces of water. If 5 people are in ellen's family. how many ounces of water do they d

Svetach [21]

Answer:

41 2/3 oz of water

Step-by-step explanation:

All you have to do is multiply 8 1/3 by 5.

First, lets convert 8 1/3 into an improper fraction (a fraction where the numerator is greater than the denominator):

8 1/3 = 25/3

now, we can multiply 25/3 by 5 and get 125/3, which simplifies to 41 2/3

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2 years ago

You want to get from a point A on the straight shore of the beach to a buoy which is 54 meters out in the water from a point B o

anyanavicka [17]

Answer:

$x =\dfrac{45 \sqrt{6}}{ 2}$

Step-by-step explanation:

From the given information:

The diagrammatic interpretation of what the question is all about can be seen in the diagram attached below.

Now, let V(x) be the time needed for the runner to reach the buoy;

∴ We can say that,

$\mathtt{V(x) = \dfrac{70-x}{7}+\dfrac{\sqrt{54^2+x^2}}{5}}$

In order to estimate the point along the shore, x meters from B, the runner should stop running and start swimming if he want to reach the buoy in the least time possible, then we need to differentiate the function of V(x) and relate it to zero.

i.e

The differential of V(x) = V'(x) =0

= $\dfrac{d}{dx}\begin {bmatrix} \dfrac{70-x}{7} + \dfrac{\sqrt{54^2+x^2}}{5} \end {bmatrix}= 0$

$-\dfrac{1}{7}+ \dfrac{1}{5}\times \dfrac{x}{\sqrt{54^2+x^2}}=0$

$\dfrac{1}{5}\times \dfrac{x}{\sqrt{54^2+x^2}}= \dfrac{1}{7}$

$\dfrac{5x}{\sqrt{54^2+x^2}}= \dfrac{1}{7}$

$\dfrac{x}{\sqrt{54^2+x^2}}= \dfrac{1}{\dfrac{7}{5}}$

$\dfrac{x}{\sqrt{54^2+x^2}}= \dfrac{5}{7}$

squaring both sides; we get

$\dfrac{x^2}{54^2+x^2}= \dfrac{5^2}{7^2}$

$\dfrac{x^2}{54^2+x^2}= \dfrac{25}{49}$

By cross multiplying; we get

$49x^2 = 25(54^2+x^2)$

$49x^2 = 25 \times 54^2+ 25x^2$

$49x^2-25x^2 = 25 \times 54^2$

$24x^2 = 25 \times 54^2$

$x^2 = \dfrac{25 \times 54^2}{24}$

$x =\sqrt{ \dfrac{25 \times 54^2}{24}}$

$x =\dfrac{5 \times 54}{\sqrt{24}}$

$x =\dfrac{270}{\sqrt{4 \times 6}}$

$x =\dfrac{45 \times 6}{ 2 \sqrt{ 6}}$

$x =\dfrac{45 \sqrt{6}}{ 2}$

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