The measures of the angles don't change when you translate a figure, because the entire figure is moving as a whole. Imagine having a paper parallelogram, moving it around and flipping it over. Not even dilations would change these angles (for reasons that can be pretty easily visualed but not really proven until geometry)
The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
<h3>Calculating wavelength </h3>
From the question, we are to determine how many times longer is the first sound wave compared to the second sound water
Using the formula,
v = fλ
∴ λ = v/f
Where v is the velocity
f is the frequency
and λ is the wavelength
For the first wave
f = 20 waves/sec
Then,
λ₁ = v/20
For the second wave
f = 16,000 waves/sec
λ₂ = v/16000
Then,
The factor by which the first sound wave is longer than the second sound wave is
λ₁/ λ₂ = (v/20) ÷( v/16000)
= (v/20) × 16000/v)
= 16000/20
= 800
Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
Learn more on Calculating wavelength here: brainly.com/question/16396485
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Total pets = 3+2 =5.
Total money = $22
Money for each pet would be:
22/5 in fraction .
$4.40 in dollars & cents.
Answer:
4(20+12) / (5-3) = 64
Step-by-step explanation:
The way to solve this problem is simple. Using PEMDAS the obvious thing to do is start with the Parentheses.....
4(20+12) / (5-3)
The way this would look after I use PEMDAS is....
4(32) / (2)
Now there are no exponents so we will now move onto the multiplication section. So we will need to multiply 32 and 4 which will leave us with 128. This now leaves us with...
128/2
Now going on to the last step we will use division since it is our last step we do not need to worry about adding or subtracting. After dividing 128 by 2 it will leave us with the answer of 64. So the answer of the equation is....
4(20+12) / (5-3) = 64
