Q4). Solve the equation 2x+1 = 2(1x/2 - 1) are represent the solution (s)
1 answer:
Answer:
<h3><u>Given :-</u></h3>2X+1 = 2 [ (1X/2)-1]
<h3><u>To find :-</u></h3>Solve the equation and represent the solution on the number line and on the Cartesian plane?
<h3><u>Solution :-</u></h3>Given equation is 2X+1 = 2 [ (1X/2)-1]
=> 2X+1 = 2[(1X-2)/2]
=> 2X+1 = 2(X-2)/2
=> 2X+1 = X-2
=> 2X-X = -2-1
=> X = -3
Therefore, X = -3
The graph is parallel to Y-axis
The coordinates are (-3,0),(-3,1),(-3,2),...
<h3><u>Scale :-</u></h3>On X - axis 1 cm = 1 unit
On Y - axis 1 cm = 1 unit
<h3><u>Answer :-</u></h3>The solution for the given equation is -3.
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<h3>What is the range of the function?</h3>Range of a function is the set of all the possible output values which are valid for that function.
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Thus, the range of the provided inverse sine function in terms of <em>x</em>, and <em>y </em>y = sin-1x is [-π/2, π/2].
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