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Leni [432]
3 years ago
10

Q4). Solve the equation 2x+1 = 2(1x/2 - 1) are represent the solution (s)

Mathematics
1 answer:
In-s [12.5K]3 years ago
8 0

Answer:

<h3><u>Given :-</u></h3>

2X+1 = 2 [ (1X/2)-1]

<h3><u>To find :-</u></h3>

Solve the equation and represent the solution on the number line and on the Cartesian plane?

<h3><u>Solution :-</u></h3>

Given equation is 2X+1 = 2 [ (1X/2)-1]

=> 2X+1 = 2[(1X-2)/2]

=> 2X+1 = 2(X-2)/2

=> 2X+1 = X-2

=> 2X-X = -2-1

=> X = -3

Therefore, X = -3

The graph is parallel to Y-axis

The coordinates are (-3,0),(-3,1),(-3,2),...

<h3><u>Scale :-</u></h3>

On X - axis 1 cm = 1 unit

On Y - axis 1 cm = 1 unit

<h3><u>Answer :-</u></h3>

The solution for the given equation is -3.

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defon

9514 1404 393

Answer:

  1. ∠EDF = 104°

  2. arc FG = 201°

  3. ∠T = 60°

Step-by-step explanation:

There are a couple of angle relationships that are applicable to these problems.

  • the angle where chords meet is half the sum of the measures of the intercepted arcs
  • the angle where secants meet is half the difference of the measures of the intercepted arcs

The first of these applies to the first two problems.

1. ∠EDF = 1/2(arc EF + arc UG)

  ∠EDF = 1/2(147° +61°) = 1/2(208°)

  ∠EDF = 104°

__

2. ∠FHG = 1/2(arc FG + arc ES)

  128° = 1/2(arc FG +55°) . . . substitute given information

  256° = arc FG +55° . . . . . . multiply by 2

  201° = arc FG . . . . . . . . . subtract 55°

__

3. For the purpose of this problem, a tangent is a special case of a secant in which both intersection points with the circle are the same point. The relation for secants still applies.

  ∠T = 1/2(arc FS -arc US)

  ∠T = 1/2(170° -50°) = 1/2(120°)

  ∠T = 60°

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3 years ago
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