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podryga [215]
3 years ago
13

What is the product in simplest form?

Mathematics
1 answer:
weqwewe [10]3 years ago
5 0

Hey there!

-89*56=-4, 984

Hope this helps!

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In the figure shown, tIl x and k Il w.
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. L find,mfksmcjccnnvjvnfkff
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The length of a rectangle is 4 inches more than its widith. The area of the rectangle is equal to 4 inches less than 3 times the
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Length is 14
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What time is 5 3/4 hours after 11:32 pm?<br> Please show work, thank you.
poizon [28]

we have to first convert fraction of hours into minutes

1 hour is equivalent to 60 minutes

then 3/4 hour is - 3/4 of 60

when the of function is used we have to multiply the 2 numbers

then \frac{3}{4} * 60 = \frac{3*60}{4} = \frac{180}{4} = 45

3/4 of an hour is equivalent to 45 minutes

then we have to add 5 hours and 45 minutes to 11.32 pm

add 5.45 to 11.32


11.32

5.45 +

-------

16.77

then its 16 hours and 77 minutes

an hour has only 60 minutes so we subtract 60 minutes from 77 minutes and add that hour to 16 hours

16 hours + 1 = 17 hours 

77 minutes - 60 minutes = 17 minutes

17 hours 17 minutes

time is given in pm therefore its a 12 hour clock

so we have to subtract 12 hours from 17 hours 17 minutes

17.17 hours - 12 hours = 5.17

the new time is 5.17 am of the next day



8 0
3 years ago
Read 2 more answers
Graph the following piecewise function on a separate piece of graph paper and upload your graph below.
Alecsey [184]
ANSWER

To graph the function

f(x)=\left \{ {{x+4\:\:if\:\:-4\leq x

follow the steps below.

1. Find y- intercept by plugging in x=0.

x=0 is on the interval,  -4\leq x, so we substitute in to

f(x)=x+4

\Rightarrow f(0)=0+4

\Rightarrow f(0)=4

Hence the y-intercept is (0,4)

2. Find x-intercept by setting f(x)=0

This implies that

x+4=0, on -4\leq x

or

2x-1=0 on 3\leq x

We now solve for x on each interval,

x=-4, on -4\leq x

or

x=\frac{1}{2} on 3\leq x

But observe that

x=\frac{1}{2} does not belong to 3\leq x

This means it  can never be an intercept for this piece-wise function.

Hence our x-intercept is (-4,0)

3. Plotting the boundaries of the interval.

For f(x)=x+4 on  -4\leq x

f(-4)=-4+4

\Rightarrow f(-4)=0.

This point (-4,0) coincides with the x-intercept.

f(3)=3+4

f(3)=7

So we have the point (3,7). But note that x=3 does not belong to this interval so we plot this point as a hole.

For f(x)=2x-1 on 3\leq x

f(3)=2(3)-1

\Rightarrow f(3)=5

So we plot (3,5)

f(6)=2(6)-1

\Rightarrow f(6)=11

So we plot (6,11) also as a hole.

Plotting all these points we can now graph the function,

f(x)=\left \{ {{x+4\:\:if\:\:-4\leq x

See attachment for graph.

7 0
3 years ago
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If p is true and q is false, the p-&gt;q is ____<br> true.<br> never<br> always<br> sometimes
ratelena [41]

Answer:

never

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but since q is false, p->q is never true

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3 years ago
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