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3 years ago

What is the answer to -3+y=-5

Mathematics

2 answers:

mihalych1998 [28]3 years ago

5 0

Answer:

y = -2

Step-by-step explanation:

-3+y = -5

1) Subtract 3 from both sides.

2) You get y = -2

Stolb23 [73]3 years ago

4 0

Answer:

y=-2

Step-by-step explanation:

you are solving for the variable y

add 3 to the opposite side, so it cancels out

y=-5+3

y=-2

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Identify all the Geometric Sequence(s) from the options below-

MAVERICK [17]

1.) Not a sequence
2.) 2^n-1
3.) Not a sequence
4.) 81/3^n-1
5.) -(-3)^n-1
6.) Not a sequence

7 0

2 years ago

Before the pandemic cancelled sports, a baseball team played home games in a stadium that holds up to 50,000 spectators. When ti

spayn [35]

Answer:

(a) $D(x)=-2,500x+60,000$

(b) $R(x)=60,000x-2500x^2$

(d)Optimal ticket price: $12

Maximum Revenue:$360,000

Step-by-step explanation:

The stadium holds up to 50,000 spectators.

When ticket prices were set at $12, the average attendance was 30,000.

When the ticket prices were on sale for $10, the average attendance was 35,000.

(a)The number of people that will buy tickets when they are priced at x dollars per ticket = D(x)

Since D(x) is a linear function of the form y=mx+b, we first find the slope using the points (12,30000) and (10,35000).

$\text{Slope, m}=\dfrac{30000-35000}{12-10}=-2500$

Therefore, we have:

$y=-2500x+b$

At point (12,30000)

$30000=-2500(12)+b\\b=30000+30000\\b=60000$

Therefore:

$D(x)=-2,500x+60,000$

(b)Revenue

$R(x)=x \cdot D(x) \implies R(x)=x(-2,500x+60,000)\\\\R(x)=60,000x-2500x^2$

(c)To find the critical values for R(x), we take the derivative and solve by setting it equal to zero.

$R(x)=60,000x-2500x^2\\R'(x)=60,000-5,000x\\60,000-5,000x=0\\60,000=5,000x\\x=12$

The critical value of R(x) is x=12.

(d)If the possible range of ticket prices (in dollars) is given by the interval [1,24]

Using the closed interval method, we evaluate R(x) at x=1, 12 and 24.

$R(x)=60,000x-2500x^2\\R(1)=60,000(1)-2500(1)^2=\$57,500\\R(12)=60,000(12)-2500(12)^2=\$360,000\\R(24)=60,000(24)-2500(24)^2=\$0$

Therefore:

Optimal ticket price:$12
Maximum Revenue:$360,000

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3 years ago

Do the following form a right triangle?<br> 20, 25, 30<br> True<br> False

qaws [65]

Answer:

False

Step-by-step explanation:

20, 25, and 30 no hagas un triángulo rectángulo

4 0

3 years ago

Read 2 more answers

Graphing Exponential Function in Exercise ,sketch the graph of the function.See example 3 and 4.

9966 [12]

Answer:

The graph is attached below.

Step-by-step explanation:

Considering the exponential function

$y=3^{-2x}$

$\mathrm{Apply\:exponent\:rule}:\quad \:a^{bx}=\left(a^b\right)^x$

$3^{-2x}=\left(3^2\right)^{-x}$

$=\left(3^2\right)^{-x}$

$=9^{-x}$

The graph is also attached below.

Keywords: exponential function, graph

Learn more about exponential function from brainly.com/question/11908487

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7 0

3 years ago

Solve for x in the equation x2 - 4x-9 = 29.

erastova [34]

Answer:

$x=2+\sqrt{21}\\\\x=2-\sqrt{21}$

Step-by-step explanation:

One is given the following equation;

$x^2-4x-9=29$

The problem asks one to find the roots of the equation. The roots of a quadratic equation are the (x-coordinate) of the points where the graph of the equation intersects the x-axis. In essence, the zeros of the equation, these values can be found using the quadratic formula. In order to do this, one has to ensure that one side of the equation is solved for (0) and in standard form. This can be done with inverse operations;

$x^2-4x-9=29$

$x^2-4x-38=0$

This equation is now in standard form. The standard form of a quadratic equation complies with the following format;

$ax^2+bx+c$

The quadratic formula uses the coefficients of the quadratic equation to find the zeros this equation is as follows,

$\frac{-b(+-)\sqrt{b^2-4ac}}{2a}$

Substitute the coefficients of the given equation in and solve for the roots;

$\frac{-(-4)(+-)\sqrt{(-4)^2-4(1)(-38)}}{2(1)}$

Simplify,

$\frac{-(-4)(+-)\sqrt{(-4)^2-4(1)(-38)}}{2(1)}\\\\=\frac{4(+-)\sqrt{16+152}}{2}\\\\=\frac{4(+-)\sqrt{168}}{2}\\\\=\frac{4(+-)2\sqrt{21}}{2}\\\\=2(+-)\sqrt{21}$

Therefore, the following statement can be made;

$x=2+\sqrt{21}\\\\x=2-\sqrt{21}$

8 0

2 years ago