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3 years ago

Find the difference 9 1/3 - 2/3

1 answer:

3 0

Answer: 9 1/3 - 2/3 = 8 2/3 .
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Note: If the answer were "8 1/3" ;

then: "8 1/3 + 2/3 =? 9 1/3 ? "

→ "8 1/3 + 2/3 = 8 3/3 = 8 + 1 = 9 = only "9" ;
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So the answer has to be MORE than "8 1/3"

Try "8 2/3" → "8 2/3 + 2/3 =? 9 1/3?" ?? ;

→ "8 2/3 + 2/3 = 8 4/3 = 8 + 1 1/3 = 9 1/3 " → Yes!
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So, the answer is: "8 2/3" .
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Another method:
_________________
Given the problem: "9 1/3 - 2/3 " ;
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Note that: "2/3 = 1/3 + 1/3"
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So, "9 1/3 - 2/3 = 9 1/3 - (1/3 + 1/3) = 9 1/3 - 1/3 - 1/3 = ?
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Start with: "9 1/3 - 2/3" = 9. Then 9 - 1/3 = 8 3/3 - 1/3 = 8 2/3.
______________________________________________________
Another method:
____________________________
Given the problem:
____________________________
"9 1/3 - 2/3 = ?? " ;
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Convert "9 1/3" into "28/3" ; ("3*9 = 27"); ("27+1=28");
(The "3" comes from the "3" in the: "1/3" portion.)
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So, we rewrite as:
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28/3 - 2/3 = (28 - 2) / 3 = 26/3 ; or, 8 2/3 .
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2 years ago

point T"(-2,5) is a vertex of triangle T"O"P". The original image was rotated 90° counterclockwise around the origin and rhen tr

emmainna [20.7K]

ANSWER

T(-2,1)

EXPLANATION

Let T(a,b) be the coordinates.

When this point is rotated 90° counterclockwise about the origin,

Then,

$T(a,b)\to \: T'( - b,a)$

If this point is then translated using the rule;

$(x,y)\to (x-1,y+7)$

then,

$T(a,b)\to \: T'( - b,a) \to T"( - b - 1,a + 7)$

It was given that, T"(-2,5)

This implies that,

-b-1=-2

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-b=-1

b=1

a+7=5

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a=-2

Therefore the coordinates of T are:

(-2,1)

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3 years ago

Read 2 more answers

Write a quadratic function f (X) for the area of a rectangle with the length of X+5 and a width of 3x-7

GarryVolchara [31]

Area = length x width
f(x) = (x + 5)(3x - 7)
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3 years ago

How do you find out if a like is parallel, perpendicular, or coincidental when theres 2 equations

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The slope intercept form of the equation of a line is given as:

y = mx + c

where m = the slope of the line

c = the y - intercept of the line

1) Two line are parallel if they have the same slope

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$\begin{gathered} \text{If the equation for line 1 is: y = m}_1x+c_1 \\ \text{If the equation for line 2 is: y = m}_2x+c_2 \\ \text{Then, line 1 is parallel to line 2 if m}_1=m_2 \end{gathered}$

2) Two equations are perpendicular if the slope of one is the negative inverse of the other.

$\text{That is : m}_1=\text{ }\frac{-1}{m_2}$

3) Two equations are coincidental if they have the same slope and the same y intercept

$\begin{gathered} \text{That is: m}_1=m_2_{} \\ \text{and c}_1=c_2 \end{gathered}$

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1 year ago