Question

Each week, Heather’s company has $5000 in fixed costs plus an additional $250 for each system produced. The company is able to produce 5 systems in one hour of production, and h represent the number of hours in production
Part a] write functions c(n) and n(h) to model this situation, explain what they represent

Part b] Then write a function c(n(h)) to represent the coat incurred in h hours. Show the work or explain the reasoning used to determine the answer

Part c] Find c(n(100)).

Part d] interpret your solution to part c

Answer 1

The question is an illustration of composite functions.

• Functions c(n) and h(n) are $\mathbf{c(n) = 5000 + 250n}$ and $\mathbf{n(h) = 5h}$
• The composite function c(n(h)) is $\mathbf{c(n(h)) = 5000 + 1250h}$
• The value of c(n(100)) is $\mathbf{c(n(100)) = 130000}$
• The interpretation is: "the cost of working for 100 hours is $130000"

The given parameters are:

• $5000 in fixed costs plus an additional $250
• 5 systems in one hour of production

(a) Functions c(n) and n(h)

Let the number of system be n, and h be the number of hours

So, the cost function (c(n)) is:

$\mathbf{c(n) = Fixed + Additional \times n}$

This gives

$\mathbf{c(n) = 5000 + 250 \times n}$

$\mathbf{c(n) = 5000 + 250n}$

The function for number of systems is:

$\mathbf{n(h) = 5 \times h}$

$\mathbf{n(h) = 5h}$

(b) Function c(n(h))

In (a), we have:

$\mathbf{c(n) = 5000 + 250n}$

$\mathbf{n(h) = 5h}$

Substitute n(h) for n in $\mathbf{c(n) = 5000 + 250n}$

$\mathbf{c(n(h)) = 5000 + 250n(h)}$

Substitute $\mathbf{n(h) = 5h}$

$\mathbf{c(n(h)) = 5000 + 250 \times 5h}$

$\mathbf{c(n(h)) = 5000 + 1250h}$

(c) Find c(n(100))

c(n(100)) means that h = 100.

So, we have:

$\mathbf{c(n(100)) = 5000 + 1250 \times 100}$

$\mathbf{c(n(100)) = 5000 + 125000}$

$\mathbf{c(n(100)) = 130000}$

(d) Interpret (c)

In (c), we have: $\mathbf{c(n(100)) = 130000}$

It means that:

The cost of working for 100 hours is $130000

Read more about composite functions at:

brainly.com/question/10830110