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3 years ago

What’s the difference between being rude and being mean?

2 answers:

7 0

I would say the difference is that being rude is the lighter version of being mean. When I think of rude I think of snarky/annoying comments and small petty actions. But when I think of mean I think of much harsher/hurtful comments and more violent actions.

SCORPION-xisa [38]3 years ago

5 0

Answer:

being rude is like having no maners.

Step-by-step explanation:

being mean is having NO COMMON SENCE OF HUMAN FEELINGS

You might be interested in

Find the mode for the following data set {1,3,5,7,9] PLS HELP

kvasek [131]

Answer: There is no mode.

Step-by-step explanation:

The mode is the number in a data set that occurs most frequently. Count how many times each number occurs in the data set. The mode is the number with the highest tally. It's ok if there is more than one mode. And if all numbers occur the same number of times there is no mode.

Hope this helps!

7 0

3 years ago

PLEASE HELP ME Multiply the monomials: a2x5b, −0.6axb2 and 0.6a2b3

Tanzania [10]

Answer:

$-0.36 a^{5}b^{6} x^{6}$

Step-by-step explanation:

Given:

$a^2x^5b,,\ -0.6axb^2,\ and\ 0.6a^2b^3$

Required

Multiply

The above can be written as

$a^2x^5b * -0.6axb^2\ * \ 0.6a^2b^3$

Split the above expression

$a^2*x^5*b * -0.6*a*x*b^2\ * \ 0.6*a^2*b^3$

Collect like terms

$-0.6 * 0.6 * a^2*a*a^2*b *b^2 *b^3*x^5*x$

Apply first law on indices

$-0.36 * a^{2+1+2} *b^{1+2+3} *x^{5+1}$

$-0.36 * a^{5} *b^{6} *x^{6}$

$-0.36 a^{5}b^{6} x^{6}$

Hence, $a^2x^5b * -0.6axb^2\ * \ 0.6a^2b^3$ is equivalent to $-0.36 a^{5}b^{6} x^{6}$

8 0

3 years ago

The final exam of a particular class makes up 40% of the final grade, and Moe is failing the class with an average (arithmetic m

amm1812

Answer:

%82.5

Step-by-step explanation:

The final exam of a particular class makes up 40% of the final grade
Moe is failing the class with an average (arithmetic mean) of 45% just before taking the final exam.

From point 1 we know that Moe´s grade just before taking the final exam represents 60% of the final grade. Then, using the information in the point 2 we can compute Moe´s final grade as follows:

$FG=0.40*FE+0.60*0.45$ ,

where FG is Moe´s Final Grade and FE is Moe´s final exam grade. Then,

$\frac{ FG-0.60*0.45}{0.40}=FE$ .

So, in order to receive the passing grade average of 60% for the class Moe needs to obtain in his exam:

$FE=\frac{ 0.60-0.60*0.45}{0.40}=0.825$

That is, he need al least %82.5 to obtain a passing grade.

6 0

3 years ago

What number is 9.5% of 20?

mars1129 [50]

1.9

9.5% = 0.095

0.095* 20 = 1.9

7 0

3 years ago

What is the range of the function f(x) = |x| +2?

kykrilka [37]

Imagine the graph of f(x)=|x|. This can only output positive values ( $x \geq 0$ ).

Then f(x)=|x|+2 is the same graph shifted upwards by two units meaning it can only output values bigger or equal to than 2. So the range is $x \geq 2$

5 0

4 years ago