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aivan3 [116]
3 years ago
11

According to the distributive property, 6(a + b) =

Mathematics
2 answers:
kkurt [141]3 years ago
7 0
With the distributive property, you multiply whatever is one the outside of the parenthesis, by each term on the inside.

6a + 6b

Also, whats with the image? Lol.
Vesnalui [34]3 years ago
7 0
I'm not sure why you attached that particular screenshot. However, if you wanted to distribute, then you simply multiply each inner term by the outer term 6

6 times a = 6a
6 times b = 6b
we don't know what 'a' or 'b' are, so we leave the expressions as is

Therefore, 6*(a+b) = 6a+6b
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A jewelry store sells charm bracelets and charms. A bracelet with two charms costs $36.00. A bracelet with four charms costs $50
Slav-nsk [51]

Answer:

36+50

Step-by-step explanation:

4 0
3 years ago
Which statement describes the inverse of m(x) = x2 – 17x?
stealth61 [152]

Answer:

The correct option is;

The \ domain \ restriction \ x \geq \dfrac{17}{2} \ results \ in \ m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}

Step-by-step explanation:

The given information is that m(x) = x² - 17·x

The above equation can be written in the form;

y = x² - 17·x

Therefore;

0 = x² - 17·x - y

From the general solution of a quadratic equation, 0 = a·x² + b·x + c we have;

x = \dfrac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}

By comparison to the equation,0 = x² - 17·x - y, we have;

a = 1, b = -17, and c = -y

Substituting the values of a, b and c into the formula for the general solution of a quadratic equation, we have;

x = \dfrac{-(-17)\pm \sqrt{(-17)^{2}-4\times (1) \times (-y)}}{2\times (1)} = \dfrac{17\pm \sqrt{289+4\cdot y}}{2}

Which can be simplified as follows;

x =  \dfrac{17\pm \sqrt{289+4\cdot y}}{2}= \dfrac{17}{2} \pm \dfrac{1}{2}  \times \sqrt{289+4\cdot y}} = \dfrac{17}{2} \pm \sqrt{\dfrac{289}{4} +\dfrac{4\cdot y}{4} }}

And further simplified as follows;

x = \dfrac{17}{2} \pm \sqrt{\dfrac{289}{4} +y }} = \dfrac{17}{2} \pm \sqrt{y + \dfrac{289}{4} }}

Interchanging x and y in the function of the inverse, m⁻¹(x), we have;

m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}

We note that the maximum or minimum point of the function, m(x) = x² - 17·x found by differentiating the function and equating the result to zero, gives;

m'(x) = 2·x - 17 = 0

x = 17/2

Similarly, the second derivative is taken to determine if the given point is a maximum or minimum point as follows;

m''(x) = 2 > 0, therefore, the point is a minimum point on the graph

Therefore, as x increases past the minimum point of 17/2, m⁻¹(x) increases to give;

The \ domain \ restriction \ x \geq \dfrac{17}{2} \ results \ in \ m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }} to increase m⁻¹(x) above the minimum.

8 0
3 years ago
The total ticket sales for a soccer game were $1.260; 210 tickets were purchased. If all
Scorpion4ik [409]
It was 6 each because 1,260 divided by 210 is 6 and PLEASE MARK BRAINLIEST
6 0
3 years ago
Read 2 more answers
Math help please, thx
pogonyaev
The answer is radical 9
5 0
3 years ago
-7w+8 (w+1)=w-7<br> Please show work
kvv77 [185]
Hello there.^••^

−7w+8(w+1)=w−7
w+8=w−7
w+8−w=w−7−w8=−7
8−8=−7−80=−15
No solutions.
6 0
3 years ago
Read 2 more answers
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