Question

Each side of a square is increasing at a rate of 6 cm/s. At what rate is the area of the square increasing when the area of the square is 16cm^2?

Answer 1

Solution: 48cm/s^2

Working:

A = s^2

Derivate s^2 (as it is area formula) which gives

dA/dt = 2s dL/dt

dL/dt = 6cm/s

Hence,

2(6) = 12

Side: 4cm

Hence,

dA/dt = (4)(12) = 48cm/s^2

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