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Anna [14]
3 years ago
5

Wesdfrgtygfyhujkilhiuh

Mathematics
1 answer:
3241004551 [841]3 years ago
4 0

Answer:

i do not know what are your talking about.

Step-by-step explanation:

what!. that's my answer.

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Simply a3 • a4 <br> And (2a) (5ab)
Tanya [424]

Answer:

a^3 (a^4) = a^7

(2a)(5ab) = 10a^2b

Step-by-step explanation:

7 0
3 years ago
A figure that has no endpoints is called a
dedylja [7]
A figure that has no endpoints is called a line.
Hope this helps you with your homework~!
8 0
3 years ago
What is the approximate value for the modal daily sales?
Aleksandr [31]

Answer:

Step-by-step explanation:

Hello!

<em>The table shows the daily sales (in $1000) of shopping mall for some randomly selected  days </em>

<em>Sales 1.1-1.5 1.6-2.0 2.1-2.5 2.6-3.0 3.1-3.5 3.6-4.0 4.1-4.5 </em>

<em>Days 18 27 31 40 56 55 23 </em>

<em>Use it to answer questions 13 and 14. </em>

<em>13. What is the approximate value for the modal daily sales? </em>

To determine the Mode of a data set arranged in a frequency table you have to identify the modal interval first, this is, the class interval in which the Mode is included. Remember, the Mode is the value with most observed frequency, so logically, the modal interval will be the one that has more absolute frequency. (in this example it will be the sales values that were observed for most days)

The modal interval is [3.1-3.5]

Now using the following formula you can calculate the Mode:

Md= Li + c[\frac{(f_{max}-f_{prev})}{(f_{max}-f_{prev})(f_{max}-f_{post})} ]

Li= Lower limit of the modal interval.

c= amplitude of modal interval.

fmax: absolute frequency of modal interval.

fprev: absolute frequency of the previous interval to the modal interval.

fpost: absolute frequency of the posterior interval to the modal interval.

Md= 3,100 + 400[\frac{(56-40)}{(56-40)+(56-55)} ]= 3,476.47

<em>A. $3,129.41 B. $2,629.41 C. $3,079.41 D. $3,123.53 </em>

Of all options the closest one to the estimated mode is A.

<em>14. The approximate median daily sales is … </em>

To calculate the median you have to identify its position first:

For even samples: PosMe= n/2= 250/2= 125

Now, by looking at the cumulative absolute frequencies of the intervals you identify which one contains the observation 125.

F(1)= 18

F(2)= 18+27= 45

F(3)= 45 + 31= 76

F(4)= 76 + 40= 116

F(5)= 116 + 56= 172 ⇒ The 125th observation is in the fifth interval [3.1-3.5]

Me= Li + c[\frac{PosMe-F_{i-1}}{f_i} ]

Li: Lower limit of the median interval.

c: Amplitude of the interval

PosMe: position of the median

F(i-1)= accumulated absolute frequency until the previous interval

fi= simple absolute frequency of the median interval.

Me= 3,100+400[\frac{125-116}{56} ]= 3164.29

<em>A. $3,130.36 B. $2,680.36 C. $3,180.36 D. $2,664</em>

Of all options the closest one to the estimated mode is C.

5 0
3 years ago
The answer for 10 2/3×31/8 rounded to the nearest whole number?
BigorU [14]
10 \frac{2}{3} ( \frac{31}{8}) can be changed into this equation:

\frac{32}{3}( \frac{31}{8}  )

The 32 and 8 have a common factor of 8 and can be simplified to become this equation:

\frac{4}{3} ( \frac{31}{1})

Now multiply across to get \frac{124}{3} which then simplifies to 41 \frac{1}{3} which as a decimal is 41.333 (repeating 3s). Nearest whole number is 41. 

Your answer is 41
5 0
4 years ago
There is a bag filled with 6 blue and 5 red marbles.
s344n2d4d5 [400]

Answer:

1/11

Step-by-step explanation:

probability =total number of items ÷ 1

=11÷1

=1/11

8 0
2 years ago
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