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Anna [14]
2 years ago
5

Wesdfrgtygfyhujkilhiuh

Mathematics
1 answer:
3241004551 [841]2 years ago
4 0

Answer:

i do not know what are your talking about.

Step-by-step explanation:

what!. that's my answer.

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Goran is on his way home in his car. He has driven 12 miles so far, which is two-thirds of the way home. What is the total lengt
Vinil7 [7]

Answer:

2/3 = 12

12/2 = 1/3

1/3 = 6

3/3 = 3x6

Whole drive = 18miles

Hopefully this helps

7 0
2 years ago
You need to rent meeting
bija089 [108]

Answer:

B. The Huddle Room, by 3 square feet

Step-by-step explanation:

9 * 11 = 99

8 * 12 = 96

99 - 96 = 3

The Huddle Room, by 3 square feet

Hope this helps!

8 0
3 years ago
Is math<br><br> a. bad<br> b. bad<br> c. bad<br> d. all of the above
Elina [12.6K]

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Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
Find the absolute maximum and absolute minimum values of f on the given interval. f(t) = 9t + 9 cot(t/2), [π/4, 7π/4]
agasfer [191]

Answer:

the absolute maximum value is 89.96 and

the absolute minimum value is 23.173

Step-by-step explanation:

Here we have cotangent given by the following relation;

cot \theta =\frac{1 }{tan \theta} so that the expression becomes

f(t) = 9t +9/tan(t/2)

Therefore, to look for the point of local extremum, we differentiate, the expression as follows;

f'(t) = \frac{\mathrm{d} \left (9t +9/tan(t/2)  \right )}{\mathrm{d} t} = \frac{9\cdot sin^{2}(t)-\left (9\cdot cos^{2}(t)-18\cdot cos(t)+9  \right )}{2\cdot cos^{2}(t)-4\cdot cos(t)+2}

Equating to 0 and solving gives

\frac{9\cdot sin^{2}(t)-\left (9\cdot cos^{2}(t)-18\cdot cos(t)+9  \right )}{2\cdot cos^{2}(t)-4\cdot cos(t)+2} = 0

t=\frac{4\pi n_1 +\pi }{2} ; t = \frac{4\pi n_2 -\pi }{2}

Where n_i is an integer hence when n₁ = 0 and n₂ = 1 we have t = π/4 and t = 3π/2 respectively

Or we have by chain rule

f'(t) = 9 -(9/2)csc²(t/2)

Equating to zero gives

9 -(9/2)csc²(t/2) = 0

csc²(t/2)  = 2

csc(t/2) = ±√2

The solutions are, in quadrant 1, t/2 = π/4 such that t = π/2 or

in quadrant 2 we have t/2 = π - π/4 so that t = 3π/2

We then evaluate between the given closed interval to find the absolute maximum and absolute minimum as follows;

f(x) for x = π/4, π/2, 3π/2, 7π/2

f(π/4) = 9·π/4 +9/tan(π/8) = 28.7965

f(π/2) = 9·π/2 +9/tan(π/4) = 23.137

f(3π/2) = 9·3π/2 +9/tan(3·π/4) = 33.412

f(7π/2) = 9·7π/2 +9/tan(7π/4) = 89.96

Therefore the absolute maximum value = 89.96 and

the absolute minimum value = 23.173.

7 0
3 years ago
Which graph shows the line y = x + 1?
Iteru [2.4K]
I need a picture in order to help

Here is a picture of a bobcat anyway

6 0
3 years ago
Read 2 more answers
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